One of the factors of 1331x^3-8y^3

1 answer:

3 0

Difference of 2 perfect squares

remember
$a^3-b^3=(a-b)(a^2+ab+b^2)$
so
$(11x)^3-(2y)^3=(11x-2y)(121x^2+22xy+4y^2)$

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