The point that the graphs of f and g have in common are (1,0)
<h3>How to get the points?</h3>
The given functions are:
f(x) = log₂x
and
g(x) = log₁₀x
We know that logarithm of 1 is always zero.
This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1
Therefore the point the graphs of f and g have in common is (1,0).
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Answer:
Step-by-step explanation:
65.00 + 65.00 = 130.00 - 65.00 = 65.00
Answer:
(3a-1)(3a+1)
Step-by-step explanation:
We can quickly see with this problem that it is the difference of two squares as 9a^2 is (3a)^2 and 1 is 1^2 and therefore can factorise quickly using this rule.
x^2-y^2 = (x-y)(x+y) where x = 3a and y = 1
2=28 divide both get 14 . So each cd is 14$. So now 28+28=56 (4 cd's) plus 14 (1 more cd) =5 so 5 is 70.
Answer:
X3 it can also be written as 3x, which is X+X+X
