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3 years ago

Nate spent $28 on 2 dvds.at this rate how much would 5 dvds cost him

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

7 0

2=28 divide both get 14 . So each cd is 14$. So now 28+28=56 (4 cd's) plus 14 (1 more cd) =5 so 5 is 70.

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John has to build a box for his scouting project with a volume of 36 cubic centimeters.

prohojiy [21]

Answer:

John should build the box 3 cm high.

Step-by-step explanation:

John should build the box 3 cm high because to find the volume you must do length x width x height. To find this you have to multiply the length x width. In this problem 6 would be the length and 2 would be the width. After multiplying those you get 12. You then have to find what number multiplies with 12 to get 36, which is 3. Hope this helped!

5 0

3 years ago

Segment PH is graphed on the coordinate grid where P is (-31,8) and H is (29,-10). Point E is the midpoint of segment PH. If poi

maks197457 [2]

Answer:

The coordinates of point A are (-11 , 2)

Step-by-step explanation:

- The coordinates of point P are (-31 , 8)

- The coordinates of point H are (29 , -10)

- Point E is the mid-point of segment PH

- The coordinates of the the mid-point are:

→ $x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is $x=\frac{-31+29}{2}=-1$

∴ The x-coordinate of point E is -1

∴ The y-coordinate of point E is $y=\frac{8+-10}{2}=-1$

∴ The y-coordinate of point E is -1

∴ The coordinates of point E are (-1 , -1)

- Point A is graphed $\frac{2}{3}$ of the way along the segment from P to E

- That mean the distances from points P to A is 2 parts and from P to E

is 3 parts, then the distance from A to E is "3 - 2" = 1 part

- So point A divides the line segment PE at ratio 2 : 1 from P

- The coordinates of the division point are:

→ $x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$ and $y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

∵ Point A divides PE at ratio 2 : 1

∵ The coordinates of point P are (-31 , 8)

∵ The coordinates of point E are (-1 , -1)

∴ The x-coordinate of point A is $x=\frac{(-31)(1)+(-1)(2)}{2+1}= -11$

∴ The x-coordinate of point A is -11

∴ The y-coordinate of point A is $x=\frac{(8)(1)+(-1)(2)}{2+1}=2$

∴ The y-coordinate of point A is 2

∴ The coordinates of point A are (-11 , 2)

* The coordinates of point A are (-11 , 2)

3 0

3 years ago

What are the intercept of 2X+3y= 6z=30

sattari [20]

The intercepts of the given equations is as given in the task content is; Choice B; (15,0,0),(0,10,0) ,(0,0,5).

<h3>What are the intercepts of the equation as give in the task content?</h3>

The x-intercept of the given equation can be determined by setting values of y and z to zero.

The y-intercept can be determined by setting x and z to zero.

While the z-intercept can be determined by setting x and y to zero.

Consequently, the X-intercept of the given equations is; 2x +3(0) = 30; x = 15.

Therefore, we have; (15,0,0)

The y-intercept is therefore; 2(0) +3y = 30; 3y = 30; y = 30/3 = 10 and. we have; (0,15,0)

And hence, the z-intercept is; z = 30/6 = 5.