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2 years ago

Heyyy i really need help with this

Mathematics

1 answer:

Kobotan [32]2 years ago

3 0

Answer:

Step-by-step explanation:

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A hiker climbs a mountain. After 1 hour he is at an altitude of 200 feet. After 3 hours, he is at an altitude of 350 feet. What

s344n2d4d5 [400]

Answer: 75 feet per hour

Step-by-step explanation:

X: 1, 3

Y: 200, 350

150/2

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2 years ago

How many triangles can be constructed with angles measuring 120°, 40°, and 10°?

balu736 [363]

Any kind of Triangle must have 180 degree of angle in total if it is not, then it is not a Triangle.

In short, Your Answer would be Zero

Hope this helps!

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2 years ago

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This was the only major battle fought in New England during the War. Twelve hundred Patriots surrounded Boston, hoping to force

Mariana [72]

Step-by-step explanation:

Bunker Hill was the name of the battle!

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2 years ago

y eggs in a basket. One quarter of the eggs are sold and four got broken. How many eggs are in the basket in term of y.

elixir [45]

1/4y-4 , hope this helps

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2 years ago

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Factor completely. <br> <img src="https://tex.z-dn.net/?f=x%5E%7B8%7D-%5Cfrac%7B1%7D%7B81%7D" id="TexFormula1" title="x^{8}-\fra

Eduardwww [97]

We have 3⁴ = 81, so we can factorize this as a difference of squares twice:

$x^8 - \dfrac1{81} = \left(x^2\right)^4 - \left(\dfrac13\right)^4 \\\\ x^8 - \dfrac1{81} = \left(\left(x^2\right)^2 - \left(\dfrac13\right)^2\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)$

Depending on the precise definition of "completely" in this context, you can go a bit further and factorize $x^2-\frac13$ as yet another difference of squares:

$x^2 - \dfrac13 = x^2 - \left(\dfrac1{\sqrt3}\right)^2 = \left(x-\dfrac1{\sqrt3}\right)\left(x+\dfrac1{\sqrt3}\right)$

And if you're working over the field of complex numbers, you can go even further. For instance,

$x^4 + \dfrac19 = \left(x^2\right)^2 - \left(i\dfrac13\right)^2 = \left(x^2 - i\dfrac13\right) \left(x^2 + i\dfrac13\right)$

But I think you'd be fine stopping at the first result,

$x^8 - \dfrac1{81} = \boxed{\left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)}$

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2 years ago