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zlopas [31]
3 years ago
7

Which is the equation for bc?

Mathematics
2 answers:
Ilya [14]3 years ago
3 0
Y=-4/5x+1 is the equation for bc
maxonik [38]3 years ago
3 0

Answer:

 y(x)=- \frac{4}{5}x+1=-0.8 x+1

Step-by-step explanation:

A line can be expressed using a slope-intercept form:

y(x)=mx+b

Where:

m=Slope=\frac{\Delta y}{\Delta x} =\frac{y_2-y_1}{x_2-x_1}

b=y-axis\hspace{3}intercept

Given a point on the line P(x_1,y_1) it is possible to obtain the previous equation from the following formula:

y-y_1=m(x-x_1)

From the graph we can extract the two points necessary to find the equation. As you can see:

B(x_1,y_1)=(-5,5)\\C(x_2,y_2)=(0,1)

So, let's find the slope:

m=\frac{1-5}{0-(-5)}= \frac{-4}{5} =-0.8

Now, we have everything we need to find the equation for BC:

y-5=-\frac{4}{5} (x-(-5))\\\\y-5=-\frac{4}{5} x-4\\\\y=-\frac{4}{5}+1=-0.8x+1

Therefore, the equation for BC is:

y(x)=- \frac{4}{5}x+1=-0.8 x+1

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y = -\frac{1}{2}x + 1

y = -2x - 4

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suppose you performed a regression analysis. you were given four observations of the target at [1.0, 1.5, 2.8, 3.7], and you pre
Arlecino [84]

Suppose you performed a regression analysis. The mse for this scenario is 0.105

Regression is a statistical method used in finance, making an investment, and different disciplines that attempt to determine the electricity and man or woman of the relationship between one established variable (commonly denoted through Y) and a sequence of different variables (called independent variables).

We are able to say that age and peak can be described through the usage of a linear regression version. because someone's peak will increase as age will increase, they have got a linear courting. Regression fashions are commonly used as statistical proof of claims regarding regular statistics.

"Regression" comes from "regress" which in turn comes from Latin "regresses" - to head returned (to something). In that feel, regression is the approach that permits "to head again" from messy, hard-to-interpret data, to a clearer and more significant version.

y ypred (y-ypred)^2

1 1.1 0.01

1.5 1.3 0.04

2.8 3.2 0.16

3.7 3.7 0

The error sum of the square is given by

ESS = (y- )

ESS=0.21

The mean square error is given by

ESS MSE = ESS/dfe

MSE = \frac{0.21}{2}

MSE = 0.105

Learn more about regression here brainly.com/question/26755306

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