Answer:
The degree of a polynomial refers to the highest degree of its individual terms having non-zero coefficients.
Step-by-step explanation:
The degree of a polynomial refers to the highest degree of its individual terms having non-zero coefficients. For example;
A quadratic polynomial is a polynomial of degree 2. This polynomial takes the general form;
where a, b, and c are constants. This is usually referred to as a quadratic polynomial in x since x is the variable. The highest power of x in the polynomial is 2, hence the degree of any quadratic polynomial is 2.
A second example, consider the cubic polynomial;

The degree of this polynomial is 3.
6 Why because my brain is huge
Answer:
dV/dt = 3×10^2 × 0.5 = 150 in^3/sec
the volume of the cube is increasing at 150in^3/sec
Step-by-step explanation:
Volume V = length l^3
V = x^3
Differentiating both sides;
dV/dt = 3x^2 dv/dt
Given;
x = 10 in
dx/dt = 0.5 in/sec
dV/dt = 3×10^2 × 0.5 = 150 in^3/sec
the volume of the cube is increasing at 150in^3/sec
Answer:
30
Step-by-step explanation:
Original Equation: 2(7 + 8)
So you have to multiply 2 by 7 which equals 14
Then you multiply 2 by 8 which equals 16
Your equation should now look like this: 14 + 16
Add 14 and 16 together.
Your answer is 30
Hope I helped :)
Please condsider brainliest
Answer: Any real number x as long as
and 
In other words, anything but 0 or -2/3 is valid.
========================================================
Explanation:
Set the denominator equal to zero and solve for x
2(3x^2 + 2x) = 0
3x^2 + 2x = 0
x(3x + 2) = 0
x = 0 or 3x+2 = 0 .... zero product property
x = 0 or 3x = -2
x = 0 or x = -2/3
If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.
Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.