Answer:

Step-by-step explanation:
A line can be expressed using a slope-intercept form:

Where:


Given a point on the line
it is possible to obtain the previous equation from the following formula:

From the graph we can extract the two points necessary to find the equation. As you can see:

So, let's find the slope:

Now, we have everything we need to find the equation for BC:

Therefore, the equation for BC is:
