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zlopas [31]
3 years ago
7

Which is the equation for bc?

Mathematics
2 answers:
Ilya [14]3 years ago
3 0
Y=-4/5x+1 is the equation for bc
maxonik [38]3 years ago
3 0

Answer:

 y(x)=- \frac{4}{5}x+1=-0.8 x+1

Step-by-step explanation:

A line can be expressed using a slope-intercept form:

y(x)=mx+b

Where:

m=Slope=\frac{\Delta y}{\Delta x} =\frac{y_2-y_1}{x_2-x_1}

b=y-axis\hspace{3}intercept

Given a point on the line P(x_1,y_1) it is possible to obtain the previous equation from the following formula:

y-y_1=m(x-x_1)

From the graph we can extract the two points necessary to find the equation. As you can see:

B(x_1,y_1)=(-5,5)\\C(x_2,y_2)=(0,1)

So, let's find the slope:

m=\frac{1-5}{0-(-5)}= \frac{-4}{5} =-0.8

Now, we have everything we need to find the equation for BC:

y-5=-\frac{4}{5} (x-(-5))\\\\y-5=-\frac{4}{5} x-4\\\\y=-\frac{4}{5}+1=-0.8x+1

Therefore, the equation for BC is:

y(x)=- \frac{4}{5}x+1=-0.8 x+1

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The velocity of a particle moving back and forth on a line is vequalsStartFraction ds Over dt EndFraction equals6 sine (2 t )Sta
max2010maxim [7]

Answer:

s = 6 m

Step-by-step explanation:

The value of the velocity v is given as:

v = \frac{ds}{dt} = 6 sin(2t) m/s

To find s, we have to integrate and apply the initial values of s = o when t = 0:

\frac{ds}{dt} = 6 sin(2t)\\\\\int\limits^s_0 {ds} = \int\limits^t_0 {6sin(2t)} \, dt\\\\s|^s_o = -3cos(2t)|^t_o\\\\s - 0 = -3cos(2t) -(-3cos(0))\\\\s = -3cos(2t) + 3(1)\\\\s = -3cos(2t) + 3

When t = π/2, s will be:

s = -3cos(2 * π/2) + 3

s = -3cos(π) + 3

s = -3(-1) + 3

s = 3 + 3

s = 6 m

4 0
3 years ago
Use the information given in the diagram. Tell why AB≈DC and
Katen [24]
AB=DC because they have the same side lengths
5 0
3 years ago
Read 2 more answers
Legs and hypotenuse ​
zaharov [31]

Answer:

Step-by-step explanation:

For a right triangle, the side that is opposite of the right angle is called the hypotenuse. This side will always be the longest side of the right triangle. The other two (shorter) sides are called legs.

3 0
3 years ago
In triangle EFG, angle E equals 8x-16, angle F equals x+8, and angle G equals 2x-10. What is the value of x?
Stels [109]

Answer: The value of x= 18

Step-by-step explanation:

Given: In triangle EFG, angle E equals 8x-16, angle F equals x+8, and angle G equals 2x-10.

The sum of all angles of a triangle is 180°.

Therefore, in triangle EFG

∠E + ∠F +∠G= 180°

⇒ 8x-16 +x+8+ 2x-10 =  180

⇒ 11x-18= 180

⇒ 11x = 180+18

⇒11x=198

⇒ x= 18   [Divide both sides by 11]

Hence, the value of x= 18

6 0
2 years ago
Patrick compared the slope of the function g(x) = -2x - 8 to the slope of the linear function shown in the table below. Let m =
Zina [86]
Both slopes have the same sign
7 0
3 years ago
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