All categories

3 years ago

Sorry the orange spot doesn’t mean anything. Can u plz help???

Mathematics

1 answer:

Tasya [4]3 years ago

7 0

Answer:

Step-by-step explanation:

-11+5=-6 therfore the sum of the two are still <-5 which makes this answer true.

You might be interested in

COMPLETE A TABLE OF VALUE FOR EACH EQUATIONS, THEN GRAPH.

gregori [183]

It’s is 1)

A black kid black white white shirt with green green red black

4 0

3 years ago

What is the answer to this equation <img src="https://tex.z-dn.net/?f=10%5Csqrt%7Bx%7D%2020" id="TexFormula1" title="10\sqrt{x}

AveGali [126]

Factor the expression
Use the properties of radicals
Simplify the roots
Calculate
And your solution will be 20 overall 5
Message me if you want me to write it all down!

8 0

3 years ago

How is this problem factored? 35x^2-57x-44

faust18 [17]

You can use the quadratic formula with it which will be easier
or simple factoring
it will be (5x-11)(7x+4)

7 0

3 years ago

Write the quadratic equation whose roots are 3 and -5, and whose leading coefficient is 2.

Rainbow [258]

$\begin{cases} x=3\implies &x-3=0\\ x=-5\implies &x+5=0 \end{cases}\qquad \implies\qquad a(x-3)(x+5)=\stackrel{0}{y} \\\\\\ a(\stackrel{F~O~I~L}{x^2+2x-15})=y\implies \stackrel{\textit{leading coefficient of 2}}{2(x^2+2x-15)}=y\implies 2x^2+4x-30=y$

Check the picture below.

5 0

3 years ago

Differentiate Vx(x + 2) with respect to x.

Travka [436]

Answer:

$y'= \frac{3x+2}{2\sqrt{x} }$

General Formulas and Concepts:

Calculus

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

$y=\sqrt{x} (x+2)$

Step 2: Rewrite

$y=x^{\frac{1}{2} } (x+2)$

Step 3: Differentiate

Product Rule [Basic Power/Chain Rule]: $y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)$
Simplify: $y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}$
Rewrite: $y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}$
Add: $y'= \frac{3x+2}{2\sqrt{x} }$

7 0

3 years ago