How are determinants used to find areas of polygons?
1 answer:
When you arrange the N points in sequence around the polygon (clockwise or counterclockwise), the area is half the magnitude of the sum of the determinants of the points taken pairwise. The N determinants will also include the one involving the last point and the first one.
For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
(1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
= (1/2)*|1 -11 +4| = 3
For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
(1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
= (1/2)*|1 -11 +4| = 3
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Height of the tower = 101.9 m
Solution:
Given data:
Angle θ = 27°
Adjacent side = 200 m
Opposite side = Height
Let height be taken as h.
The given image shows it is a right triangle.
Using basic trigonometric ratio formulas,
The value of tan 27° = 0.5095
Do cross multiplication, we get
0.5095 × 200 = h
101.9 = h
Height of the tower = 101.9 m