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4 years ago

Need help with number 31 plz.

Mathematics

1 answer:

marta [7]4 years ago

3 0

$y=\dfrac{1}{3}x\\\\x=0\to\dfrac{1}{3}x=\dfrac{1}{3}(0)\to y=0\to(x,\ y)=(0,\ 0)\\\\x=1\to\dfrac{1}{3}x=\dfrac{1}{3}(1)\to y=\dfrac{1}{3}\to(x,\ y)=\left(1,\ \dfrac{1}{3}\right)\\\\x=2\to\dfrac{1}{3}x=\dfrac{1}{3}(2)\to y=\dfrac{2}{3}\to(x,\ y)=\left(2,\ \dfrac{2}{3}\right)$

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