Find the GCF of -10c 2 d and 15cd 2.

THIS QUESTION IS WORTH 15 POINTS

ikadub [295]

Answer:

3.7

This means that the answer is past the 3 point on the number line and 3 tick marks before the 4 point.

5 0

3 years ago

Which equation has no solution? O |-*-31 = 5 12x - 1) = 0 O15-3x = -8 |-* + 9 = 0

harkovskaia [24]

A because it’s the first one I saw and it looks correct

4 0

3 years ago

A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the

a_sh-v [17]

Answer:

Probability that the sample proportion will be less than 0.03 is 0.10204.

Step-by-step explanation:

We are given that a courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the true proportion is 0.04.

Also, 469 are sampled.

Let $\hat p$ = sample proportion

The z-score probability distribution for sample proportion is given by;

Z = $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion

p = true proportion = 0.04

n = sample size = 469

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample proportion will be less than 0.03 is given by = P( $\hat p$ < 0.03)

P( $\hat p$ < 0.03) = P( $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < $\frac{0.03-0.04}{\sqrt{\frac{0.03(1-0.03)}{469} } }$ ) = P(Z < -1.27) = 1 - P(Z $\leq$ 1.27)

= 1 - 0.89796 = 0.10204

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.27 in the z table which has an area of 0.89796.

Therefore, probability that the sample proportion will be less than 0.03 is 0.10204.

5 0

3 years ago

A cognitive psychologist would like to evaluate the claim that the omega-3 fatty acids can help improve memory in normal adult h

bogdanovich [222]

Answer:

(a)

Independent Variable- Dosage of Omega-3 Fatty Acids

Dependent Variable - Number of news item remembered

(b)Discrete

(c)Ratio Scale and Discrete Variable

(d) Experimental Method

Step-by-step explanation:

The psychologist wants to evaluate the claim that omega-3 fatty acids can help improve memory in normal adult humans.

(a)In the study, the participants in the two groups were given fish extracts containing Omega-3 (500 mg) and no Omega-3 (0 mg).

The memory test involves measuring the number of items each participant remembers from the past three weeks of news.

Therefore:

Independent Variable- Dosage of Omega-3

Dependent Variable - Number of news item remembered

(b) The dependent variable is discrete since the number of news items remembered can only be whole numbers.

(c)The independent variable is in milligrams of Omega-3 where the placebo is 0 mg. This is a ratio scale since it has an absolute zero.

Since the dosage is given in multiples of 50mg, it is a discrete variable.

(d)Since the psychologist seeks to manipulate the conditions of the study by introducing Omega-3 to some of the participants and placebo to other participants, it is an experimental distribution.

5 0

3 years ago

WILL GIVE BRAINLIEST TO BEST RESPONSE!

Monica [59]

You are given the X value, replace x with 2 in the first equation to solve for y:

y=2x +3

y = 2(2) +3

y = 4+3

y = 7

Now replace y with 7 and x iwth 2 in the second equation and solve for k:

y = -x +k

7 = -2 +k

Add 2 to both sides:

9 = k

so k = 9

The point is given as k-2, which is 9-2 = 7, which is what y equals in the first equation.

K = 9

5 0

3 years ago