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QveST [7]
3 years ago
12

Which set of data has the weakest linear association?

Mathematics
1 answer:
motikmotik3 years ago
5 0
The top left-hand corner set of data has the weakest linear association.

Hope that helped!!! :)
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Which of the following is the same as 2.3×10^3
gregori [183]
The answer would be C) 2,300.
7 0
3 years ago
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Prove this trigonometric equation;<br><br> - tan^2x + sec^2x = 1,
alekssr [168]
Hey there :)

- tan²x + sec²x = 1    or    1 + tan²x = sec²x

sin²x + cos²x = 1 
Divide the whole by cos²x

\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}

\frac{sinx}{cosx} = tanx so \frac{sin^2x}{cos^2x} = tan^2x
and
\frac{1}{cosx} = secx so \frac{1}{cos^2x} = sec^2x

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

3 0
3 years ago
I need help with this please
Nookie1986 [14]

Answer:

steps below

Step-by-step explanation:

3.2.1   AD = DB* sin 2 = DB * sin θ   .. DE // AB   ∠2= θ  ... (1)

By laws of sines:  DB / sin ∠5 = x / sin ∠4    

∠4 = θ-α     ∠5 = 180°-<u>∠1</u>-∠4 = 180°-<u>∠3</u>-∠4 = 180°-(90°-θ)-(θ-α)) = 90°+α

DB = (x*sin ∠5)/sin (θ-α)

     = (x* sin (90°+α)) / sin (θ-α)

AD = DB*sinθ

     = (x* sin (90°+α))*sinθ / sin (θ-α)

     = x* (sin90°cosα+cos90°sinα)*sinθ / sin (θ-α)    .... sin90°=1, cos90°=0

     = x* cosα* sinθ / sin (θ-α)

3.2.2 Please apply Laws of sines to calculate the length

7 0
2 years ago
For brainiest:):):):):):):):)
mrs_skeptik [129]

Answer:

11) to know the 20% of 70$ we need to 70÷100×20 = 14 now the sale price will ne 70-14$ = 56$

12) same 20% of 92= 92÷100×20= 18.4 $ so now original price= 92+18.4 = 110.4

13) same 40% of 30$ = 30÷100×40 = 12$ now selling price = 30-12$= 18$

3 0
3 years ago
Read 2 more answers
Help pls i need this done asap ty
zhuklara [117]

Answer:

b) 7.89*10^4

c) 3.15*10^3

Step-by-step explanation:

2-42)

the coefficient in scientific notation (the number that is not 10^x) has to be greater or equal to 1 and less than 10. so c and b are incorrect.

b) 0.789*10^5

c) 31.5*10^2

b) 0.789*10^5

in order to make 0.789 greater than 1, I would just multiply it by 10. shown below

=0.789*10*10*10*10*10

=7.89*10*10*10*10

=7.89*10^4

c) 31.5*10^2

same concept but this time divide by 10 to make 3.15 which will add another *10 to the exponent

=31.5*10*10

=3.15*10*10*10

=3.15*10^3

6 0
2 years ago
Read 2 more answers
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