Answer:
y = 2(x-3)^2 -12
y = -4/9(x-2)^2 +7 bonus
Step-by-step explanation:
The vertex form of a parabola is
y = a(x-h)^2 + k where (h,k) is the vertex
y = a(x-3)^2 - 12
We have one point given (0,6)
6 = a (0-3) ^2 -12
6 = a (-3)^2 -12
6 = 9a-12
Add 12 to each side
6+12 = 9a
18 = 9a
Divide each side by 9
18/9 = 9a/9
a=2
y = 2(x-3)^2 -12
We follow the same steps for the bonus
y = a(x-2)^2 +7
Substitute the point into the equation
3 = a (-1-2)^2 +7
3 =a (-3)^2 +7
3 = 9a +7
subtract 7 from each side
3-7 = 9a +7-7
-4 = 9a
Divide by 9
-4/9 =a
y = -4/9(x-2)^2 +7
Can you show me a picture of the problem?
a. 
has an average value on [5, 11] of
b. The mean value theorem guarantees the existence of 
such that 
. This happens for
Answer:
11.49yrs
Step-by-step explanation:
300*29% = 87
87/ 1000 = 11.49 (symplified)
my answer may not be accurate but HEY! at least im trying.
:( but i do hope this helps really.
Answer:
58
Step-by-step explanation:
I think
