Question

Last year, Susan had 10,000 to invest. She invested some of it in an account that paid 6%

Answer 1

Answer:

In the account that paid 6% Susan invest $\ 6,000$

In the account that paid 5% Susan invest $\ 4,000$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

Part a) account that paid 6% simple interest per year

in this problem we have

$t=1\ years\\ P=\ x\\r=0.06$

substitute in the formula above

$I1=x(0.06*1)$

$I1=0.06x$

Part b) account that paid 5% simple interest per year

in this problem we have

$t=1\ years\\ P=\ 10,000-\ x\\r=0.05$

substitute in the formula above

$I2=(10,000-x)(0.05*1)$

$I2=500-0.05x$

we know that

$I1+I2=\ 560$

substitute and solve for x

$0.06x+500-0.05x=560$

$0.01x=560-500$

$0.01x=60$

$x=\ 6.000$

therefore

In the account that paid 6% Susan invest $\ 6,000$

In the account that paid 5% Susan invest $\ 4,000$