6*(-5)-3 = -33
6*(-3/2)-3 = -12
6*(7/2)-3 = 18
6*(1)-3=3
Answer:
23.54 m
Step-by-step explanation:
Applying
cos∅ = adjacent(A)/hypotenuse(H)
cos∅ = A/H................ Equation 1
make H the subject of the equation
H = A/cos∅............ Equation 2
Given: A = 15 m, ∅ = 25°
Substitute into equation 2
H = 15/cos25
H = 16.55 m
Also,
tan∅ = opposite(O)/Adjacent(A)
tan∅ = O/A............Equation 3
Make O the subject of the equation
O = Atan∅.......... Equation 4
Substituting into equation 4
O = 15(tan25°)
O = 6.99 m.
From the diagram,
The height of the goal post before snap = H+O
The height of the goal post before snap = 16.55+6.99
The height of the goal post before snap = 23.54 m
5n + (-6) = -2
add 6 to -2
5n = -2 + 6
5n = 4
divide both sides by 5
n = 4/5
Answer:
18=2x
x=9
Step-by-step explanation:
hope it helps bro
PQ would be 4 square root 6 times square root of 2, which is also 4 square root 12. Simplified, it would be 8 square root 3