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timama [110]
3 years ago
15

Many of the special staff teams require leadership training, which is offered to staff with more than 1 year of service at Camp

Bright Firewood. Dean wants to identify the staff members eligible for leadership training in the table.
In cell M2, enter a formula using a nested IF function and structured references to determine first if a staff member already has completed Academic Technology training, and if not, whether that staff member is eligible for Academic Technology training.
If the value of the Leadership Training column is equal to the text "Yes", the formula should return the text Completed. Remember to use a structured reference to the Leadership Training column.If the value of the Leadership Training column is not equal to yes, the formula should determine if the value in the Service Years column is greater than 1.The formula should return the text Yes if the staff member’s Service Years value is greater than 1.The formula should return the text No if the staff member’s Service Years value is not greater than 1.
Computers and Technology
1 answer:
Sveta_85 [38]3 years ago
8 0

Answer:

The answer to this question can be defined as follows:

Explanation:

In the given question attachment file is missing so, following the code to this question:

using function IF:

=IF(Logical test, how to do it when testing is right, how to do it when testing is wrong)

In this scenario, a leader development Worker should pass 2 tests

In the First test may not finish his training

If yes-" satisfied"  

It is not true, it will go to 2nd test  

In the second test, If employee served a service period of even more than 1 year (to be performed in a first check if not correct)

If, It is yes=" yes"  else  not ="No"  

= IF(Leader Training = Yes, "Completed," IF(Service time> 1," Yes ","No")  

That's means,  

The sort IF(I2 = "Yes","Completed"),IF(D2>1," Yes","No") must be used in cell M2)

Copy Cell M2 Then the selected M3 over M30

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