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3 years ago

Sari is studying four different samples of materials. This table shows the mass and volume of the samples.

Chemistry

2 answers:

andre [41]3 years ago

7 0

Answer:

x: liquid

Explanation:

i got it right

gregori [183]3 years ago

5 0

Answer:

X: Liquid

Explanation:

As we know that there are 3 states of matter :

Solid state : It is a state in which the particles are closely packed and does not have any space between them. This state have a definite shape and volume.

Thus sample Z is solid.

Liquid state : It is a state in which the particles are present in random and irregular pattern. The particles are closely arranged but they can move from one place to another. This state have a definite volume but does not have a fixed shape.

Thus sample X is liquid.

Gaseous state : It is a state in which the particles are loosely arranged and have a lot of space between them. This state have indefinite volume as well as shape. Thus samples W and Y are gases.

Thus sample X is liquid

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Rearrange the following equation and solve for x when the hydrogen ion concentration is 0.001 M.

erastovalidia [21]

Answer : The correct option is, x = 10

Explanation : Given,

Concentration of $H^+$ ion = 0.001 M

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

First we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (0.001)$

$pH=3$

Now we have to calculate we the value of 'x'.

The given expression is:

$pH=2+\log x$

Now put the value of pH in this expression, we get:

$3=2+\log x$

$3-2=\log x$

$1=\log x$

$x=10$

Therefore, the value of 'x' is 10.

4 0

4 years ago

Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h

bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

We know that,

The relation between the $C_p\text{ and }C_v$ for an ideal gas are :

$C_p-C_v=R$

As we are given :

$C_p=28.253J/K.mole$

$28.253J/K.mole-C_v=8.314J/K.mole$

$C_v=19.939J/K.mole$

Now we have to calculate the entropy change of the gas.

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

$\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J$

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. $(w=-pdV)$

(C) Heat during the process will be,

$q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J$

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0

4 years ago

If an 85.0 mL container of helium gas at standard pressure is heated from 20.oC to 91oC and the pressure is increased to 2.8 atm

erastovalidia [21]

Answer: V₂ = 37.71mL

Explanation: To determine the new volume of Helium gas, use the Combined Gas Law, which states the following relationship among pressure, volume and temperature:

$\frac{P_{1}V_{1}}{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}$

where index 1 relates to the initial state of the gas and index 2 to the final state of the gas.

Temperature is in Kelvin, so:

T = °C + 273

For this situation, standard pressure is 1 atm. Temperatures will be:

T₁ = 20 + 273 = 293 K

T₂ = 91 + 273 = 364 K

Solving:

$V_{2}=\frac{T_{2}P_{1}V_{1}}{P_{2}T_{1}}$

$V_{2}=\frac{364*1*85}{2.8*293}$

$V_{2}=\frac{30940}{820.4}$

$V_{2}=$ 37.71

The new volume of He gas is 37.71 mL.

5 0

3 years ago

2. Which one of the following chemical equations is balanced? A. 2NaCl + H2SO4 → HCL + NaSO4 B. NH3 + H2O → 2NH4OH C. 2Na + S →

Lady_Fox [76]

D. KOH + H₂SO₄ → KHSO₄ + H₂O

6 0

4 years ago

Read 2 more answers

Which sample of matter has the greatest distance molecules at STP?

Vlada [557]

Gases

Explanation:

At standard temperature and pressure, gases have the greatest distance between their molecules. Gases are the most random state of matter of all the three known state of matter.

There are three states of matter which are solid, liquid and gas.
The particles or molecules of a gas are very far apart and are held together by very weak attractive forces.
Liquids are much more closely held together by stronger attractive forces while those of a solid are the most closely held together by very strong attractive forces.
Typical examples of gases are helium, oxygen gas e.t.c.

Learn more:

gases brainly.com/question/7966903

states of matter brainly.com/question/1511197?source=aid8343617

#learnwithBrainly

5 0

3 years ago