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3 years ago

Sari is studying four different samples of materials. This table shows the mass and volume of the samples.

Chemistry

2 answers:

andre [41]3 years ago

7 0

Answer:

x: liquid

Explanation:

i got it right

gregori [183]3 years ago

5 0

Answer:

X: Liquid

Explanation:

As we know that there are 3 states of matter :

Solid state : It is a state in which the particles are closely packed and does not have any space between them. This state have a definite shape and volume.

Thus sample Z is solid.

Liquid state : It is a state in which the particles are present in random and irregular pattern. The particles are closely arranged but they can move from one place to another. This state have a definite volume but does not have a fixed shape.

Thus sample X is liquid.

Gaseous state : It is a state in which the particles are loosely arranged and have a lot of space between them. This state have indefinite volume as well as shape. Thus samples W and Y are gases.

Thus sample X is liquid

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In any nuclear reaction, nuclei are transformed in some way.<br> TRUE<br> FALSE

stepladder [879]

Yep that is true. These are rxns that change the nucleus

3 0

3 years ago

Read 2 more answers

The decomposition of hydrogen peroxide was studied, and the following data were obtained at a particular temperature: Time (s) (

harina [27]

Answer:

Part a: The rate of the equation for 1st order reaction is given as $Rate=k[H_2O_2]$

Part b: The integrated Rate Law is given as $[H_2O_2]=[H_2O_2]_0 e^{-kt}$

Part c: The value of rate constant is $7.8592 \times 10^{-4} s^{-1}$

Part d: Concentration after 4000 s is 0.043 M.

Explanation:

By plotting the relation between the natural log of concentration of $H_2O_2$ , the graph forms a straight line as indicated in the figure attached. This indicates that the reaction is of 1st order.

Part a

Rate Law

The rate of the equation for 1st order reaction is given as

$Rate=k[H_2O_2]$

Part b

Integrated Rate Law

The integrated Rate Law is given as

$[H_2O_2]=[H_2O_2]_0 e^{-kt}$

Part c

Value of the Rate Constant

Value of the rate constant is given by using the relation between 1st two observations i.e.

t1=0, M1=1.00

t2=120 s , M2=0.91

So k is calculated as

$-k(t_2-t_1)=ln{\frac{M_2}{M_1}}\\-k(120-0)=ln{\frac{0.91}{1.00}}\\k=\frac{-0.09431}{-120}\\k=7.8592 \times 10^{-4} s^{-1}$

The value of rate constant is $7.8592 \times 10^{-4} s^{-1}$

Part d

Concentration after 4000 s is given as

$-k(t_2-t_1)=ln{\frac{M_2}{1.0}}\\-7.8592 \times 10^{-4}(4000-0)=ln{\frac{M_2}{1.00}}\\-3.1437=ln{\frac{M_2}{1.00}}\\M_2=e^{-3.1437}\\M_2=0.043 M$

Concentration after 4000 s is 0.043 M.

7 0

3 years ago

What is the Ea for the exothermic reaction A)332.6 kJ B)-85.1 kJ C)251.0 kJ D) -251.0 kJ

Lina20 [59]

Answer:

Option C. 251 kJ

Explanation:

The activation energy (Ea) of a given reaction is the minimum energy that must be overcomed for reactant to proceed to product.

The activation energy (Ea) can be obtained from an energy profile diagram by simply calculating the difference between the energy of the activation complex (i.e the peak) and the energy of the reactant.

Thus, we can obtain the activation energy for the reaction above as follow:

Activation complex = 332.6 kJ

Energy of reactant = 81.6 kJ

Activation energy =?

Activation energy = Activation complex – Energy of reactant

Activation energy = 332.6 – 81.6

Activation energy = 251 kJ

Therefore, the activation energy of the reaction is 251 kJ

5 0

4 years ago

Sterling silver contains silver and copper metals. if a sterling silver chain contains 17.6g of silver and 2.40g of copper, what

Bogdan [553]

Answer:- 0.88

Solution:- Masses of silver and copper metals are given and we are asked to calculate the percentage of silver in the alloy.

mass percent of Ag = $(\frac{mass of Ag}{mass of alloy})*100$

Mass of Ag = 17.6 g

mass of Cu = 2.40 g

mass of alloy = 17.6 g + 2.40 g = 20.0 g

Let's plug in the values in the formula:

mass percentage of Ag = $(\frac{17.6}{20.0})*100$

mass percentage of Ag = 88%

So, the mass percentage of silver in sterling silver is 88% and in decimal form it is 0.88.

7 0

3 years ago

What is the oxidation number of sulfur in BaSO4?

____ [38]

Answer:

Explanation:

We are given;

Compound BaSO₄

We are required to determine the oxidation number of S in the compound.

We need to know that;

The total oxidation number of this compound is Zero
Oxidation number of Ba metal is +2
Oxidation number of Oxygen atom is -2
There is 1 atom of Ba, 1 atom of S and 4 atoms of O in the compound.

Therefore; assuming oxidation number of S is x

Then, (1× 2) + (1 × x) + ( 4 ×(-2)) = 0

2 + x - 8 = 0

x = 6 or +6

Thus oxidation number of Sulfur in BaSO₄ is +6.

7 0

3 years ago