Answer:
45.3°C
Explanation:
Step 1:
Data obtained from the question.
Initial pressure (P1) = 82KPa
Initial temperature (T1) = 26°C
Final pressure (P2) = 87.3KPa.
Final temperature (T2) =.?
Step 2:
Conversion of celsius temperature to Kelvin temperature.
This is illustrated below:
T(K) = T(°C) + 273
Initial temperature (T1) = 26°C
Initial temperature (T1) = 26°C + 273 = 299K.
Step 3:
Determination of the new temperature of the gas. This can be obtained as follow:
P1/T1 = P2/T2
82/299 = 87.3/T2
Cross multiply to express in linear form
82 x T2 = 299 x 87.3
Divide both side by 82
T2 = (299 x 87.3) /82
T2 = 318.3K
Step 4:
Conversion of 318.3K to celsius temperature. This is illustrated below:
T(°C) = T(K) – 273
T(K) = 318.3K
T(°C) = 318.3 – 273
T(°C) = 45.3°C.
Therefore, the new temperature of the gas in th tire is 45.3°C
Answer:11.19
Explanation:
And one mole of a hydrogen atom is of 1.008 grams. So, 2 hydrogen moles weighs 2.016 grams. Hence, one mole of water has 2.016 grams of hydrogen mole. Therefore, the percentage composition of hydrogen would be 2.016/18.0152 = 11.19%.
Answer: The main sections of an airplane include:
fuselage: The plane’s body, or fuselage, holds the aircraft together, with pilots sitting at the front of the fuselage, passengers and cargo in the back.
Wings: An aircraft’s wings are critical to flight through the production of lift, but they have many parts of the wing to control this lift amount and direction.
Cockpit: The cockpit is the area at the front of the fuselage from which a pilot operates the plane
Engine: The engine(s), or powerplant, of an aircraft creates thrust needed for the plane to fly.
Propeller: An aircraft’s propeller(s) are airfoils, similar to a wing, installed vertically to create thrust to drive the plane forward.
Tail assembly: An aircraft’s tail is mainly used for stability, as well as creating lift in combination with the wings. It’s comprised of several parts.
Landing gear: Landing gear is located under the belly of the plane consisting of a wheel and strut to soften impact with the ground and may be retractable into the fuselage.
Explanation:
Answer:
0.01 M
Explanation:
The chemist is performing a serial dilution in order tyo obtain the calibration curve for the instrument.
First we must obtain the concentration of the solution in the 250ml flask from
C1V1 = C2V2
Where;
C1 = concentration of the stock solution
V1 = volume of the stock solution
C2 = concentration of the diluted solution
V2= volume of the diluted solution
2.61 × 10 = C2 × 250
C2 = 2.61 × 10/250
C2 = 0.1 M
Hence for solution in 100ml flask;
0.1 × 10 = C2 × 100
C2 = 0.1 × 10/100
C2 = 0.01 M
