<em>PQR with vertices P(–2, 9), Q(7, –3), and R(–2, –3)</em>
<em>first distance P(–2, 9), Q(7, –3) </em>
<em>The distance (d) between two points is given by the following formula: </em>
<em>Answer= 15</em>
There could be problems like there is a light which would flicker in every 7 seconds and there is another one which would flicker in every 8 seconds. So, how many times would they flicker until they would flicker at the same time?
Domain is x # 0
A case of a polynomial
By the pythagorean theorem the diagonal length will be:
d^2=x^2+y^2 and since this is a square x=y so
d^2=2x^2 and since d=15
225=2x^2
x^2=112.5
x=√112.5 yds
x≈10.6 yds (to nearest tenth of a yard)
Step-by-step explanation:
M(8.-2), M'(x,y) ,
=(-5,1)

--> x - 8 = -5 --> x= 3
---> y+2 = 1 --> y =-1
so M'(3,-1) and its reflection y-axis is (-3,-1)