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Aleksandr-060686 [28]
3 years ago
8

I need help my question is 4/7 divided by -13/5

Mathematics
2 answers:
notka56 [123]3 years ago
7 0

Answer:

-20/91

Step-by-step explanation:

Cloud [144]3 years ago
6 0
I remember how to divide fractions by doing keep, change, flip. “Keep” means keeping the first fraction the same. The “change” means changing the division to multiplication. Lastly the “flip” means switching the numerator and the denominator. So, you would solve 4/7 times -5/13 . Multiply the numerator and denominator. So the answer would be, -20/91
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the correct answer would be Y! i took it!! make me most brainlessly please!!!

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Jenny had $17 more than Susan, and together they had enough money to buy a game for $93 and to have a pizza for $6. How much mon
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. A Gardener has 6203 plants. He wants to plant this in such a way that the number of rows and the number of columns remain the
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38

Step-by-step explanation:

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5 0
3 years ago
Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
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lys-0071 [83]
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3 years ago
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