<span>The
content of any course depends on where you take it--- even two courses
with the title "real analysis" at different schools can cover different
material (or the same material, but at different levels of depth).
But yeah, generally speaking, "real analysis" and "advanced calculus"
are synonyms. Schools never offer courses with *both* names, and
whichever one they do offer, it is probably a class that covers the
subject matter of calculus, but in a way that emphasizes the logical
structure of the material (in particular, precise definitions and
proofs) over just doing calculation.
My impression is that "advanced calculus" is an "older" name for this
topic, and that "real analysis" is a somewhat "newer" name for the same
topic. At least, most textbooks currently written in this area seem to
have titles with "real analysis" in them, and titles including the
phrase "advanced calculus" are less common. (There are a number of
popular books with "advanced calculus" in the title, but all of the ones
I've seen or used are reprints/updates of books originally written
decades ago.)
There have been similar shifts in other course names. What is mostly
called "complex analysis" now in course titles and textbooks, used to be
called "function theory" (sometimes "analytic function theory" or
"complex function theory"), or "complex variables". You still see some
courses and textbooks with "variables" in the title, but like "advanced
calculus", it seems to be on the way out, and not on the way in. The
trend seems to be toward "complex analysis." hope it helps
</span>
Part A:
There are 25 blocks for the length, and the length of each is 5.5 inches. 5.5x25=137.5
There are 9 blocks for the height, and each is 2.75 inches. 2.75x9=24.75
Since we're trying to find how much longer the length is to the width, we find the difference. 137.5-24.75=112.75
So part A answer is <em><u>112.75 (or 112¾)</u></em>
Part B:
We know the length is 137.5 and the height is 24.75. To find how many times longer the length is, we need to divide to see how many 24.75 can go into 137.5.
137.5÷24.75=5.55
So the answer to part B is <u><em>5.55. Given the context, the answer would probably be 5, because that's how many entire height can fit.</em></u>
<u><em /></u>
Sorry if it's wrong lol
Answer:
2a+8
Step-by-step explanation:
Answer:
57 rows
Step-by-step explanation:
Since each row will have a total of 9 seats, then we would simply need to divide the total number of individuals that will attend the show by 9 in order to calculate the number of rows that need to be set up around the performing ring.
513 / 9 = 57 rows
Therefore, we can see that we would need a total of 57 rows of 9 chairs each in order for there to be enough chairs to seat 513 people.
Answer:
-1/4
Step-by-step explanation:
