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Luba_88 [7]
3 years ago
10

\div \frac{1}{3} + 1" alt="9 - 3 \div \frac{1}{3} + 1" align="absmiddle" class="latex-formula">
i need help with math problem​
Mathematics
1 answer:
Sveta_85 [38]3 years ago
3 0

Given:

The expression is

9-3\div \dfrac{1}{3}+1

To find:

The value of given expression.

Solution:

We have,

9-3\div \dfrac{1}{3}+1

BODMAS : Bracket, Order, Division, Multiplication, Addition, and Subtraction.

Using BODMAS, first we need to perform division in the given expression.

=9-(3\div \dfrac{1}{3})+1

=9-(3\times 3)+1

=9-9+1

Now, apply addition.

=(9+1)-9

=10-9

Now, apply subtraction.

=1

Therefore, the value of given expression is 1.

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If -2 is a zero the polynomial 3x^2+2x+k, find the value of k​
UNO [17]

Answer:

value of K =16

I hope it's helps you

4 0
3 years ago
Which value of "a" would make the following statement true? 6(2x+a)=12x+30
Serga [27]

Answer:

A) 5

Step-by-step explanation:

6(2x+a)=12x+30

6*2x+6*a=12x+30

12x+6x=12x+30

6a=12x+30-12x

6a=30

a=30/6

a=5

8 0
3 years ago
Read 2 more answers
Suppose that an automobile manufacturer designed a radically new lightweight engine and wants to recommend the grade of gasoline
yawa3891 [41]

Answer:

B) 4.07

Step-by-step explanation:

First we need to calculate the mean of all the data, which is the same as the mean of the means of each grade of gasoline:

Regular    BelowRegular   Premium   SuperPremium

39.31             36.69                38.99             40.04

39.87            40.00                40.02             39.89

39.87            41.01                  39.99             39.93

X1⁻=39.68    X2⁻= 39.23       X3⁻= 39.66    X4⁻=  39.95

Xgrand⁻ = (39.68+39.23+39.66+39.95)/4 = 39.63

Next we need to calculate the sum of squares within the group (SSW) and the sum of squares between the groups (SSB), and the respective degrees of freedom):

SSW = [ (39.31-39.68)² + (39.87-39.68)² + (39.87-39.68)² ] + [ (36.69-39.23)² + (40.00-39.23)² + (41.01-39.23)² ] + [ (38.99-39.66)² + (40.02-39.66)² + (39.99-39.66)² ] + [ (40.04-39.95)² + (39.89-39.95)² + (39.93-39.95)² ] = [0.2091] + [10.2129] + [0.6874] + [0.0121] = 11.12

SSW =  11.12

Degrees of freedom in this case is calculated by m(n-1), with m being the number of grades of gasoline (4) and n being the number of trial results for each one (3), so we would have 4(3-1) = 8 degrees of freedom

SSB = [ (39.68-39.63)² + (39.68-39.63)² + (39.68-39.63)²] + [ (39.23-39.63)² + (39.23-39.63)² + (39.23-39.63)² ] + [ (39.66-39.63)² + (39.66-39.63)² + (39.66-39.63)² ] + [ (39.95-39.63)² + (39.95-39.63)² +(39.95-39.63)² ] = [0.0075] + [0.48] + [0.0027] + [0.3072] = 0.7974

SSB =  0.80

For this case, the degrees of freedom are m-1, so we would have 4-1 = 3 degrees of freedom

Now we can establish the hypothesis for the test:

H0: μ1 = μ2 = μ3 = μ4

The null hypothesis states that the means of miles per gallon for each fuel are the same, indicating that the drade of gasoline does not make a difference, therefore our alternative hypothesis will be:

H1: the grade of gasoline does makes a difference

We will use the F statistic to test the hypothesis, which is calculated like follows:

F - statistic = (SSB/m-1) / (SSW/m(n-1)) = (0.80/3) / (11.12/8) = 0.19

We know that the level of significance we are using is α = 0.05, so to find the critical value F we need to look at some table of critical values for the F distribution for the 0.05 significance level (like the attached image). Then we just need to look fot the value that is located in the intersection between the degrees of freedom we have in the numerator (horizontal) and the denominator (vertical) of the statistic (3 and 8). That critical value is:

Fc = 4.07

3 0
3 years ago
How do u solve 63=-9d?
Len [333]
-9d = 63
you divide both side by -9

sooo...

d = -7
7 0
3 years ago
A concrete pillar has the shape of a cylinder. It has a radius of 4 meters and a height of 9 meters. If concrete costs $87 per c
otez555 [7]

Answer:

28425.13

Step-by-step explanation:

Plug in the radius and height, and then multiply by 87.

Formula : A=2πrh+2πr2

6 0
3 years ago
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