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2 years ago

Suppose you estimated square root of 12 by averaging a square like rectngle.What would be a reasonable estimation?

Mathematics

1 answer:

sesenic [268]2 years ago

5 0

Answer:

3.5.

Step-by-step explanation:

3^2 = 9

and 4^2 = 16 so the square root is between 3 and 4.

Take a rectangle 3.4 by 3.6:

the area = 3.4 * 3.6 = 12.24 so an estimate of the square root could be 3.5.

3.5 * 3.5 = 12.25.

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Dennis_Churaev [7]

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3 years ago

What is 5/18 + 7/12?

Flauer [41]

5/18+7/12

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3 years ago

Read 2 more answers

. Ralph’s Fill Dirt and Croissant Shop in Spencer makes both grand and petit croissants. Each grand requires 1 ounce of flour an

Gwar [14]

Answer:

Step-by-step explanation:

let G be the number of grand croisssants, and P the number of petit croissants :

we have that 1 ounce of flour and 2 ounces of butter result in one G.

additionally, we have that 1/4 ounce of flour and 1/3 ounce of butter result in one P.

Ralph has 4 ounces of flour and 6 ounces of butter, If he bakes more than 1 G then he will never use all of his ingredients!, let's see:

1 G:

he now has 3 ounces of flour, and 4 ounces of butter,

now we need to figure out how many P's we would obtain with such amounts:

let x be the number of P's

$1/4*x = 3=>x=12\\ 1/3*x=4=>x=12$

which is reasonable, Ralph can bake 12 P's,

now with more than 1 G:

2G:

Ralph has now 2 ounces of flour and 2 ounces of butter, now we have to figure out that x is the same using the remaining ingredients

$1/4*x = 2=>x=8\\ 1/3*x=2=>x=6$

This is impossible.

3G:

he runs out of butter.

There is the answer, he is able to bake 1 grand croissant and 12 petit croissants

7 0

3 years ago

The line shown represents the amount of money Ben owes on his lunch account.

nasty-shy [4]

Answer:

y=2x-1

Step-by-step explanation:

Remeber to put no spaces on the test

and it is this answer bc he owes one dollar evryday and owing is negative

7 0

3 years ago

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

Question 1 a. i) Find the value of x.

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

Question 1a ii) Find the volume of the frustrum

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

Question 1b. Calculate the volume of the bin

i) Upper frustrum

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

ii) Lower frustrum

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

iii) Add the volume of the two frustrums

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago

Suppose you estimated square root of 12 by averaging a square like rectngle.What would be a reasonable estimation?​

Suppose you estimated square root of 12 by averaging a square like rectngle.What would be a reasonable estimation?