Simplify the following

scoundrel [369]

(), (64)
i think that these are the subsets but im not completely sure

3 0

3 years ago

Setler [38]

$55 / 5 =$11

unit rate $11

answer
$11 per shirt

7 0

3 years ago

jeyben [28]

Answer:

(a) 0.119

(b) 0.1699

Solution:

As per the question:

Mean of the emission, $\mu = 11.7$ million ponds/day

Standard deviation, $\sigma = 2.8$ million ponds/day

Now,

(a) The probability for the water pollution to be at least 15 million pounds/day:

$P(X\geq 15) = P(\frac{X - /mu}{\sigma} \geq \frac{15 - 11.7}{2.8})$

$P(X\geq 15) = P(Z \geq 1.178)$

$P(X\geq 15)$ = 1 - P(Z < 1.178)

Using the Z score table:

$P(X\geq 15)$ = 1 - 0.881 = 0.119

The required probability is 0.119

(b) The probability when the water pollution is in between 6.2 and 9.3 million pounds/day:

$P(6.2 < X < 9.3) = P(\frac{6.2 - 11.7}{2.8} < \frac{X - \mu}{\sigma} < \frac{9.3 - 11.7}{2.8})$

$P(6.2 < X < 9.3) = P(- 1.96 < Z < - 0.86)$

P(Z < - 0.86) - P(Z < - 1.96)

Now, using teh Z score table:

0.1949 - 0.025 = 0.1699

4 0

3 years ago

maks197457 [2]

X-y=-1
x+y=5
y=x+1
x+x+1=5
2x+1=5
2x=4
x=2
y=x+1
y=2+1
y=3

4 0

3 years ago

xxMikexx [17]

Answer:

after sprouting it lived for 100 days

Step-by-step explanation:

6 0

3 years ago