Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
2) 1 4/5
3) 2
4) 4 1/3
5) 3 4/8 or 3 1/2
6) 6 2/8
You had 12 the next day and the day after that you had 18
Answer:
1539 cubic meters
Step-by-step explanation:
Hello, I can help you with this
to solve need we will need these two equations
Step one
Remember
area of a circle

Also, the volume of the cylinder
Volume= area of the circle * height

Step 2
put the values into the equation
Let
diameter= 14 m
height = 10 m

I hope it helps,have a great day.
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