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1 year ago

Use the Properties of Equality to solve each equation.

1 answer:

6 0

The answer is -25

All you have to do is add -6-9 which equals -25 because “same signs add(+) and keep” “different signs subtract(-)” but “add” means positive number and “subtract” means negative number. Since they are different signs a (+) and a (-) you subtract it.

Hope this helps!

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Ne4ueva [31]

She bought 8 bags of candy since 10 multiplied by eight is 80 and 8 is two less than ten.(ten candies in each bag)

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3 years ago

Help please. anything would help.

Nataly_w [17]

Answer:

Option a) 1/5 is most closely to 0.

8 0

2 years ago

Read 2 more answers

triangle abc is graphed on a coordinate plane, as shown below. Triangle ABC is dilated by a scale factor of 2 with a center of d

Mademuasel [1]

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3 years ago

Item 12 You win an online auction for a toy. Your winning bid of $52 is 65% of your maximum bid. How much more were you willing

nataly862011 [7]

Answer:

$28

Step-by-step explanation:

Given that:

Value of Winning bid = $52

Winning bid 65% of the maximum bid.

To find:

How much more is the maximum bid from the winning bid ?

Solution:

We are given that the winning bid is 65% of the maximum bid.

Using this percentage value, we need to first find the value of maximum bid and then we need to subtract the value of winning bid from the maximum bid to find the answer.

Let the value of maximum bid = $ $x$

As per question statement:

$65%\ of\ x = 52\\\Rightarrow \dfrac{65}{100} \times x =52\\\Rightarrow 5x = 400\\\Rightarrow x = \dfrac{400}{5}\\\Rightarrow x =\$80$

Therefore, maximum bid = $80

Our answer is:

$80 - $52 = <em>$28</em>

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3 years ago

Find all points having an x-coordinate of 2 whose distance from the point (-1,-2) is 5

mariarad [96]

$The\ equation\ of\ the\ circle:(x-a)^2+(y-b)^2=r^2\\\\where\ (a;\ b)\ -the\ coordinates\ of\ the\ center;\ r-the\ radius\\-----------------------------\\(-1;-2)-the\ center\ of\ the\ circle\\r=5\\\\The\ equation:(x+1)^2+(y+2)^2=5^5\\\\Put\ x=2\ to\ the\ equation:\\\\(2+1)^2+(y+2)^2=25\\3^2+(y+2)^2=25\\9+(y+2)^2=25\\(y+2)^2=25-9\\(y+2)^2=16\iff y+1=\pm\sqrt{16}\\\\y+1=-4\ or\ y+1=4\ \ \ \ \ |subtract\ 1\ from\ both \sides\\y=-5\ or\ y=3\\\\Answer:(2;-5)\ and\ (2;\ 3).$

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3 years ago