Question

A circle with radius 3 has a sector with a central angle of 1/9 pi radians

Answer 1

Complete question:

A circle with radius 3 has a sector with a central angle of 1/9 pi radians

what is the area of the sector?

Answer:

The area of the sector = $\frac{\pi}{2}$ square units

Step-by-step explanation:

To find the area of the sector of a circle, let's use the formula:

$A = \frac{1}{2} r^2 \theta$

Where, A = area

r = radius = 3

$\theta = \frac{1}{9}\pi$

Substituting values in the formula, we have:

$A = \frac{1}{2}*3^2* \frac{1}{9}\pi$

$A = \frac{1}{2}*9* \frac{1}{9}\pi$

$A = 4.5 * \frac{1}{9}\pi$

$A = \frac{\pi}{2}$

The area of the sector = $\frac{\pi}{2}$ square units