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rewona [7]
3 years ago
15

For the graph x = -42 find the slope of a line that is perpendicular to it and the slope of a line parallel to it. Explain your

answer with two or more sentences.
Mathematics
1 answer:
tamaranim1 [39]3 years ago
7 0
X - 42 is a straight vertical line passing through  -42 on the x-axis ( point -42,0)
so the slope is infinite .
Another line with same slope  and parallel to it would be x = 36.

A horizontal like with slope 0  is perpendicular to it  It would have equation y  any number  so y = 6 would be an example.
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Question is attached.
Gemiola [76]
1. c
2. b
3. a
hope this helps
4 0
3 years ago
the sum of the first nine terms of an arithmetic series is 162, and the sum of the first 12 terms is 288. Determine the first fi
Natali5045456 [20]

Answer:

\boxed{\pink{\tt \leadsto Sum \ of \ first \ five \ terms \ is \ 50 . }}

Step-by-step explanation:

Given that , the sum of the first nine terms of an arithmetic series is 162 and the sum of the first 12 terms is 288.

\boxed{\red{\bf \bigg\lgroup For \ answer \ refer \ to \ attachment \bigg\rgroup  }}

<h3><u>Related</u><u> </u><u>Infor</u><u>mation</u><u> </u><u>:</u><u>-</u><u> </u></h3>

• The sum of n terms of an AP is

\boxed{\orange{\sf S_n = \dfrac{n}{2}[2a+(n-1)d] }}

• nth term of an AP is given by ,

\boxed{\blue{\sf T_n = a+(n-1)d }}

8 0
2 years ago
6. David gets 65 chocolates an hour for cleaning. He gets a 15% raise. He
Sonja [21]

Answer:

Before raise: 65 chocolates/hour*60=3900 chocolates

Raise=65 * (15%=15/100=.15) .15=9.75 more chocolates per hour

With raise 74.75 chocolates/hour*60=4485 chocolates

4485-3900=585 more chocolates per 60 hour week

Step-by-step explanation:

7 0
2 years ago
PLZ HELP!! Which real numbers are zeroes of the function?
astra-53 [7]

The correct answers are: 1/2, 2 and -2.


To get this, factor f(x)

f(x)=2x^3-x^2-8x+4

f(x)= (2x^3-x^2) - (8x -4)

f(x)= (2x-1)(x^2) + (2x-1)(-4)

f(x)= (2x-1)(x^2-4)

f(x)= (2x-1)(x-2)(x+2)


2x-1=0

2x=1

x=1/2


x-2=0

x=2


x+2=0

x=-2


5 0
3 years ago
10 computer operators can compose 120 pages in 2 hours. How many operators should work, if the same job is to be completed in 30
cupoosta [38]

Answer:

40 Operators

Step-by-step explanation:

if 10 operators worked on 120 pages for 2 hours

P operators will work on the same pages for 30min

note: 2hrs= 120min

10×120min/120= P × 30/120

  • cross multiply
  • make P subject of the formula

P= 10×120×120/120×30

P = 40 operators

6 0
3 years ago
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