To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:

"d" represents the distance and coordinates are expressed as follows: (x, y)
Let's go to the calculations.
The answer is 10 uc.
Think of thermometer the negative degrees are the coldest so are the lowest on the vertical column
first convert -14 1/5 to decimals = -14.2
so the order is
-14.4 , -14 1/5 , -14.
The distance of 1 to -13 is 14.
Five sixths of this is (.8333*14), which equals 11.6667.
Answer:
Step-by-step explanation:
Given
Joaquin's score is 
and Trisha's score is 
Arranging score in order of value we get
Joaquin's : 
Trisha's : 
as no of values is even therefore their median is
Joaquin's
Trisha's 
Therefore median of Joaquin's is lower
Thus Joaquin wins the game
Answer:
Step-by-step explanation:
Sin 21 = 
Sin 21 = 
0.3583 = 
0.3583*15 = BC
BC = 5.3745 = 5.37 m
Tan ∅ = 
Tan ∅ = 
∅ = tan⁻¹ (0.7448) = 36.67 = 36.7