The volume of the given rectangular prism is option C.
.
Step-by-step explanation:
Step 1:
The dimensions of the given rectangular prism are 4 units × 3 units × 2 units.
So we take the length equals 4 units, the width is equal to 3 units and the height is 2 units.
Step 2:
The volume of this rectangular prism is calculated by multiplying the given prism's length, its width, and its height.
The Volume of the given rectangular prism = ![( Length) (Width) (Height) = (4units) (3units) (2 units) = 24 unit^{3} .](https://tex.z-dn.net/?f=%28%20Length%29%20%20%28Width%29%20%28Height%29%20%3D%20%284units%29%20%20%283units%29%20%20%282%20units%29%20%3D%2024%20unit%5E%7B3%7D%20.)
So the given right rectangular prism's volume is
which is option C.
Answer:
![\mu_{\hat{p}}=0.19](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%7Bp%7D%7D%3D0.19)
![\sigma_{\hat{p}}=0.0785](https://tex.z-dn.net/?f=%5Csigma_%7B%5Chat%7Bp%7D%7D%3D0.0785)
Step-by-step explanation:
We know that the mean and the standard error of the sampling distribution of the sample proportions will be :-
![\mu_{\hat{p}}=p](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%7Bp%7D%7D%3Dp)
![\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}](https://tex.z-dn.net/?f=%5Csigma_%7B%5Chat%7Bp%7D%7D%3D%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D)
, where p=population proportion and n= sample size.
Given : The proportion of students at a college who have GPA higher than 3.5 is 19%.
i.e. p= 19%=0.19
The for sample size n= 25
The mean and the standard error of the sampling distribution of the sample proportions will be :-
![\mu_{\hat{p}}=0.19](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%7Bp%7D%7D%3D0.19)
![\sigma_{\hat{p}}=\sqrt{\dfrac{0.19(1-0.19)}{25}}\\\\=\sqrt{0.006156}=0.0784601809837\approx0.0785](https://tex.z-dn.net/?f=%5Csigma_%7B%5Chat%7Bp%7D%7D%3D%5Csqrt%7B%5Cdfrac%7B0.19%281-0.19%29%7D%7B25%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B0.006156%7D%3D0.0784601809837%5Capprox0.0785)
Hence , the mean and the standard error of the sampling distribution of the sample proportions :
![\mu_{\hat{p}}=0.19](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%7Bp%7D%7D%3D0.19)
![\sigma_{\hat{p}}=0.0785](https://tex.z-dn.net/?f=%5Csigma_%7B%5Chat%7Bp%7D%7D%3D0.0785)
I think it is B because it has a continuous line soy it couldn’t be a. It has negative numbers so it couldn’t be D. And it has negative numbers so couldn’t be C
let's plug the value of x and y as 5 and 4 respectively to find the value of given expression :