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Nadya [2.5K]
2 years ago
8

Last year a business had profits of $8,000.This year its profits are 5 times as great.This are this year's profits?

Mathematics
1 answer:
Solnce55 [7]2 years ago
7 0
$40,000 in profits this year
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Help Me Pls Thank You
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Answer: It's b

Step-by-step explanation:

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What is the value of (-140 ^0) ^ -2​
BigorU [14]
The answer is 1 because anything Raised to the power of zero will always be one in one to the power of -2 will be one
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One zero of x3 – 3x2 – 6x + 8 = 0 is -2. What are the other zeros of the function?
hram777 [196]
Consider this solution, if it is possible, check the result:
1) if to divide polynomial 'x³-3x²-6x+8' on 'x+2' result is: x²-5x+4, then x³-3x²-6x+8=(x+2)(x²-5x+4);
2) x²-5x+4=(x-1)(x-4), then
3) x³-3x²-6x+8=(x+2)(x-1)(x-4).
4) zeros are: -2;1;4. Other zeros are: 1 and 4.
Answer: 1;4.
7 0
3 years ago
What value of x is in the solution set of 4x – 12 ≤ 16 + 8x?
gtnhenbr [62]
The solution for the x-value in this set is -7≤x
4 0
3 years ago
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Ví dụ 1.5. Một người đi mua hàng 3 lần. Xác suất lần đầu mua được hàng tốt là 0,7.
vodka [1.7K]

Answer:

a) 0.50575,

b) 0.042

Step-by-step explanation:

Example 1.5. A person goes shopping 3 times. The probability of buying a good product for the first time is 0.7.

If the first time you can buy good products, the next time you can buy good products is 0.85;  (I interpret this as, if you buy a good product, then the next time you buy a good product is 0.85).

And if the last time I bought a bad product, the next time I bought a good one is  0.6. Calculate the probability that:

a) All three times the person bought good goods.

P(Good on 1st shopping event AND Good on 2nd shopping event AND Good on 3rd shopping event) =

P(Good on 1st shopping event) *P(Good on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st and 2nd shopping events yield Good) =

(0.7)(0.85)(0.85) =

0.50575      

b) Only the second time that person buys a bad product.

P(Good on 1st shopping event AND Bad on 2nd shopping event AND Good on 3rd shopping event) =

P(Good on 1st shopping event) *P(Bad on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st is Good and 2nd is Bad shopping events) =

(0.7)(1-0.85)(1-0.6) =

(0.7)(0.15)(0.4) =

0.042

5 0
2 years ago
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