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Georgia [21]
3 years ago
7

Select the quadratic equation that has roots x=8 and x=-5

Mathematics
1 answer:
stellarik [79]3 years ago
5 0

Step-by-step explanation:

Since, x=8 and x=-5 are the roots.

Therefore, (x - 8) & (x - 5) will be factors.

Hence, required quadratic equation can be given as:

(x - 8)(x - 5) =0 \\  \\  \therefore  {x}^{2}  + ( - 8 - 5) x+ ( - 8) \times ( - 5) = 0 \\  \\ \therefore  {x}^{2}  + ( - 13) x+ 40= 0  \\  \\ \huge \red{ \boxed{ \therefore  {x}^{2}  - 13x+ 40= 0 }} \\ is \: the \: required \: quadratic \: equation.

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3 years ago
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The height above ground level of a rider on a roller coaster over the duration of the ride

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4 0
3 years ago
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3 years ago
Find the probability of being dealt a full house. (Round your answer to six decimal places.)?
vesna_86 [32]

I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.

A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.

Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.

The number of ways of drawing 2 aces and 3 2s is

\dbinom42\dbinom43=24

and the number of ways of drawing 3 aces and 2 2s is the same,

\dbinom43\dbinom42=24

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.

Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

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The total number of hands that can be drawn is

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\dfrac{2\binom{13}2\binom42\binom43}{\binom{52}5}=\dfrac6{4165}\approx\boxed{0.001441}

4 0
3 years ago
This is LCM and GCF I think
Ugo [173]
Yes it is LCM and GCF because you are trying to a factor that they both have
3 0
3 years ago
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