6xy -3x -8y +4
3x (2y - 1 ) - 4 (2y -1)
(2y-1) (3x-4)
There are 5 tenths, 6 hundredths, and 3 thousandths. The first decimal is the tenths, the second decimal is the hundredths, and the third decimal is the thousandths.
54 55 59 61 61 62 68 70 72
First put your numbers in order from least to greatest. This shows your minimum is 54 and maximum is 72.
In the middle of the data set is 61.
54 55 59 61. 61. 62 68 70 72
To find the first qaurtile only use the numbers before rhe median (54 55 59 61) and find the median of that. Since 55 and 59 are both in the middle add them both and divide by two to find the middle lf those two numbers. You should get 57. So 57 is the first quartile.
Do the same steps with the numbers after the meadian for your third quartile. You should get 69 as your answer for the third quartile.
(7-4)=3
<span>(8-5)=3 </span>
<span>now we have </span>
<span>2*3+6 / 3+3 </span>
<span>2*3 is 6 </span>
<span>now we have </span>
<span>6+6/3+3 </span>
12/6
<span>2</span>
