How much of a 60% acid solution must be mixed with 50 gallons of a 24% acid solution to obtain a solution that is 50% acid?
2 answers:
X gallons of a 60% acid solution contains 60%×x=0.6x gallons of acid.
50 gallons of a 24% acid solution contains 24%×50=0.24×50=12 gallons of acid.
After mixing, there will be x+50 gallons of a solution, and 0.6x+12 gallons of acid. The concentration must be 50%, so the volume of acid divided by the volume of the solution is 50%, or 0.5.
The answer is A. 130 gallons.
50 gallons of a 24% acid solution contains 24%×50=0.24×50=12 gallons of acid.
After mixing, there will be x+50 gallons of a solution, and 0.6x+12 gallons of acid. The concentration must be 50%, so the volume of acid divided by the volume of the solution is 50%, or 0.5.
The answer is A. 130 gallons.
You might be interested in
Hey there :)
Writing in scientific notation means a should be
0 ≤ a < 10
Therefore, 0.000309 will be written as
3.09 x 10ⁿ
3 is the 4th decimal place value
so n = - 4
3.04 x 10⁻⁴
Writing in scientific notation means a should be
0 ≤ a < 10
Therefore, 0.000309 will be written as
3.09 x 10ⁿ
3 is the 4th decimal place value
so n = - 4
3.04 x 10⁻⁴