Question

How much of a 60% acid solution must be mixed with 50 gallons of a 24% acid solution to obtain a solution that is 50% acid?

Answer 1

X gallons of a 60% acid solution contains 60%×x=0.6x gallons of acid.
50 gallons of a 24% acid solution contains 24%×50=0.24×50=12 gallons of acid.

After mixing, there will be x+50 gallons of a solution, and 0.6x+12 gallons of acid. The concentration must be 50%, so the volume of acid divided by the volume of the solution is 50%, or 0.5.

$\frac{0.6x+12}{x+50}=0.5 \\ 0.6x+12=0.5(x+50) \\ 0.6x+12=0.5x+25 \\ 0.6x-0.5x=25-12 \\ 0.1x=13 \\ 0.1x \times 10=13 \times 10 \\ x=130$

The answer is A. 130 gallons.

Answer 2

Answer:

a. 130

Step-by-step explanation: