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2 years ago

Write an equation in slope-intercept form of the line that passed through (-3, 4) and (1. 4).

1 answer:

5 0

The two points share the same y coordinate, which means that the line is horizontal, and this in turn means that the slope is 0.

Since a line written in slope-intercept form is

$y=mx+q$

In the case of m=0 the equation is

$y=q$

where the constant $q$ is the common y coordinate shared by all points.

So, in your case, the equation is

$y=4$

You might be interested in

Evaluate.

tekilochka [14]

Step-by-step explanation:

W=-6, x=1.2, and z=-6/7

(W²x-3)÷10-z

we substitute

((-6²)(1.2)-3)÷10-(-6/7)

((-36)(1.2)-3) ÷10-(-6/7)

(-43.2-3) ÷10(6/7)

(-46.2)÷60/7

-46.2÷60/7

-46.2*7/60

-46.2/1*7/60

-323.4/60

-5.39

8 0

2 years ago

The expression 14s(s - 1) can be used to find

Fantom [35]

Answer:

B. The variable s represents the number of students in each class.

C. The coefficient 14 represents the number of classes in the 9th grade.

Step-by-step explanation:

The total number can be found by multiplying the number of the things with the number of people producing it. For example if 5 boys make 5 colored ropes the total number of ropes will be 5*5= 25.

In this question the combinations rule is used for variuos number of classes which are 14. Now we have to find the number of students which are s (s-1). Suppose s= 6 so the number of students would be 6(6-1) = 6(5) = 30

We will multiply the number of classes 14 with the number of students s(s-1) to get the total number of cards produced.

6 0

2 years ago

35 into binary number<br>

vodka [1.7K]

Answer:

35 in binary is 100011.

Step-by-step explanation:

To find decimal to binary equivalent, divide 35 successively by 2 until the quotient becomes 0.

4 0

2 years ago

Read 2 more answers

Plz help: The density of water is 1.0g/ml. Which of the following will float when dropped in water?

yarga [219]

Answer:

Hey I think that it's a cube of sodium or ice

Step-by-step explanation:

Hope it helps! :)

$*GraceRosalia*$

6 0

2 years ago

Read 2 more answers

find the spectral radius of A. Is this a convergent matrix? Justify your answer. Find the limit x=lim x^(k) of vector iteration

Natasha_Volkova [10]

Answer:

The solution to this question can be defined as follows:

Step-by-step explanation:

Please find the complete question in the attached file.

$A = \left[\begin{array}{ccc} \frac{3}{4}& \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2}& 0\\ -\frac{1}{4}& -\frac{1}{4} & 0\end{array}\right]$

now for given values:

$\left[\begin{array}{ccc} \frac{3}{4} - \lambda & \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2} - \lambda & 0\\ -\frac{1}{4}& -\frac{1}{4} & 0 -\lambda \end{array}\right]=0 \\\\$

$\to (\frac{3}{4} - \lambda ) [-\lambda (\frac{1}{2} - \lambda ) -0] - 0 - \frac{1}{4}[0- \frac{1}{2} (\frac{1}{2} - \lambda )] =0 \\\\\to (\frac{3}{4} - \lambda ) [(\frac{\lambda}{2} + \lambda^2 )] - \frac{1}{4}[\frac{\lambda}{2} - \frac{1}{4}] =0 \\\\\to (\frac{3}{8}\lambda + \frac{3}{4} \lambda^2 - \frac{\lambda^2}{2} - \lambda^3 - \frac{\lambda}{8} + \frac{1}{16}=0 \\\\\to (\lambda - \frac{1}{2}) (\lambda -\frac{1}{4}) (\lambda - \frac{1}{2}) =0\\\\$

$\to \lambda_1=\lambda_2 =\frac{1}{2}\\\\\to \lambda_3 = \frac{1}{4} \\\\\to A = max {|\lambda_1| , |\lambda_2|, |\lambda_3|}\\\\$

$= max{\frac{1}{2}, \frac{1}{2}, \frac{1}{4}}\\\\= \frac{1}{2}\\\\(A) =\frac{1}{2}$

In point b:

Its

spectral radius is less than 1 hence matrix is convergent.

In point c:

$\to c^{(k+1)} = A x^{k}+C \\\\\to x(0) = \left(\begin{array}{c}3&1&2\end{array}\right) , c = \left(\begin{array}{c}2&2&4\end{array}\right)\\\\ \to x^{(k+1)} = \left[\begin{array}{ccc} \frac{3}{4}& \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2}& 0\\ -\frac{1}{4}& -\frac{1}{4} & 0\end{array}\right] x^k + \left[\begin{array}{c}2&2&4\end{array}\right] \\\\$

after solving the value the answer is

$\lim_{k \to \infty} x^k=o = \left[\begin{array}{c}0&0&0\end{array}\right]$

4 0

2 years ago