The answer is 4900 because you add the 6,400+1,800=8,200 then you subtract the 8,200-3,300= 4,900
Answer: A; 6.3%
Step-by-step explanation:
Problem 1
For the first problem, we first want to find y so that we can plug it into the expression.
We can use elimination method for the system of equations to solve.
3x+3y=21
3x-y=5
We subtract both equations to eliminate x.
4y=16 [divide both sides by 4]
y=4
Now that we know y, we can plug it into the expression.
[divide]
[subtract]

We know that the answer is A.
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Problem 2
For the second problem, we need to know how to calculate percent error. The formula for precent error is
. We know that the exact value is 80 because the buyer was supposed to given 80. 75 is the measured value because that was what the buyer was given.
[subtract]
[solve absolue value]
[divide]
[multiply]

Since the problem said to round to one decimal place, we know that the answer is 6.3%.
Answer:
Communitive Property
Step-by-step explanation:
Commutative property = 2 + 3 = 3 + 2 or 2(3) = 3(2)
Associative Property = (2 x 3) 5 = 2 (3 x 5) or (2 + 3) + 5 = 2 + (3 + 5)
Inverse Property = 2 + (-2) = 0 or (2/1)(½) = 1
Basic Definitions:
<u><em>Commutative Property</em></u> - Gives you the ability to switch the order of the numbers in an expression.
<u><em>Associative Property</em></u> - Let's you move the parenthesis in an expression but not the numbers.
<u><em>Inverse</em></u> - Uses numbers like 0 and 1.
Using these basic definitions and examples, we can summarize that the best answer would be <u>Communitive Property</u>
<u></u>
Answer:
1) False. 2) True. 3) True. 4) False.
Step-by-step explanation:
1) False. The force of gravity will drive it down. The path will form a parabola.
2) True. There is no variation in the velocity in the horizontal axis and no force applied so the acceleration is zero.
3) True. The travel time depends on the height and the acceleration of gravity, and independent of the velocity of the rocket at launch.
4) False. The travel distance depends on the initial velocity of the rocket (at launch).