A box contains 10 red , 3 blue, and 7 white balls , two balls are drawn at random from the box on after the other without replac
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Given equation : n(17+x)=34x−r.
We need to solve it for x.
Distributing n over (17+x) on left side, we get
17n + nx = 34x - r.
Adding r on both sides, we get
17n+r + nx = 34x - r+r.
17n + r + nx = 34x.
Subtracting nx from both sides, we get
17n + r + nx-nx = 34x-nx
17n + r = 34x -nx.
Factoring out gcf x on right side, we get
17x + r = x(34-n).
Dividing both sides by (34-n), we get
To calculate the square root, you can either use the √symbol on a calculator or you can manually find it using Prime Factorization. For non-perfect squares, Prime Factorization is the way to go.
The first two steps work for solving large perfect squares as well.
1. Divide your number into perfect square factors.
2. Take the square roots of your perfect square factors.
3. If your number doesn't factor perfectly, reduce your answer to simplest terms.
4. If needed, estimate. In some cases if you have memorized some of the square roots, you can estimate where the number would be.
ie.
you know that 
and 
, so you can estimate that the would be between 7 and 8 but closer to 8.
5. <span>Alternatively, reduce your number to its lowest common factors as your first step.</span><span> Finding perfect square factors isn't necessary if you can easily determine a number's prime factors (factors that are also prime numbers).
ie. </span>
=
=
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Hope this helped!!!
The first two steps work for solving large perfect squares as well.
1. Divide your number into perfect square factors.
2. Take the square roots of your perfect square factors.
3. If your number doesn't factor perfectly, reduce your answer to simplest terms.
4. If needed, estimate. In some cases if you have memorized some of the square roots, you can estimate where the number would be.
ie.
5. <span>Alternatively, reduce your number to its lowest common factors as your first step.</span><span> Finding perfect square factors isn't necessary if you can easily determine a number's prime factors (factors that are also prime numbers).
ie. </span>
=
=
=
Hope this helped!!!