N = 3 ( the next number is 3 plus the previous number
sequence formula = an = 3(n-1) +2
so for term the term that =59
59 = 3(n-1) +2
distribute:
59 = 3n -3+2
59 = 3n -1
60 = 3n
n = 60/3
n = 20
59 is the 20th term
Answer:
By the Central Limit Theorem, the sampling distribution of the sample mean amount of money in a savings account is approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Average of 1,200 dollars and a standard deviation of 900 dollars.
This means that
Sample of 10.
This means that
The sampling distribution of the sample mean amount of money in a savings account is
By the Central Limit Theorem, approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.
Answer:
range of scores on final exam student get B is 90 to 100
Step-by-step explanation:
given data
Psychology 101 score = 66
average of his midterm = between 78 and 90
maximum = 100 points
to find out
range of scores on final exam student get B
solution
we consider here lowest marks need in final = x
so average at two marks should be
equation is
average marks = 0.5 × ( mid term marks + final marks ) .................1
put here value
78 = 0.5 × ( 66 + x )
x = 90
and
90 = 0.5 × ( 66 + x )
x = 114
so range 90 to 114
but maximum marks is 100 so
range of scores on final exam student get B is 90 to 100
13. A=(-1,3) 14.m= (-4,1)
Answer:
D : 10ab√2a+20a√2a
Step-by-step explanation: