![\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20~~~~~~%5Ctextit%7Bin%20feet%7D%20%5C%5C%5C%5C%20h%28t%29%20%3D%20-16t%5E2%2Bv_ot%2Bh_o%20%5Cend%7Barray%7D%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Cstackrel%7B64%7D%7B%5Ctextit%7Binitial%20velocity%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h_o%3D%5Cstackrel%7B0%5Cqquad%20%5Ctextit%7Bfrom%20the%20ground%7D%7D%7B%5Ctextit%7Binitial%20height%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Bheight%20of%20the%20object%20at%20%22t%22%20seconds%7D%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
![\bf h(t)=-16t^2+64t+0\implies h(t)=-16t^2+64t\implies \stackrel{\textit{hits the ground}~\hfill }{0=-16t^2+64t} \\\\\\ 0=-16t(t-4)\implies t= \begin{cases} 0\\ \boxed{4} \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20h%28t%29%3D-16t%5E2%2B64t%2B0%5Cimplies%20h%28t%29%3D-16t%5E2%2B64t%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bhits%20the%20ground%7D~%5Chfill%20%7D%7B0%3D-16t%5E2%2B64t%7D%20%5C%5C%5C%5C%5C%5C%200%3D-16t%28t-4%29%5Cimplies%20t%3D%20%5Cbegin%7Bcases%7D%200%5C%5C%20%5Cboxed%7B4%7D%20%5Cend%7Bcases%7D)
Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.
93 x 10^6 =
93 x 1,000,000 = 93,000,000
1/2 is the probability, or 50%. There are 4 teams of S and B n the Y, 2 are B. so its 2/4
Do you guys do common core becase there would be two type's of a surface area!
Answer:
63in
Step-by-step explanation: