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3 years ago

11

A diver descends from an elevation of 6 feet below sea level to an elevation of 98 feet below sea level in 4 equal intervals.wha

t was the divers change in elevation in each interval?explain how you solved this problem

1 answer:

Inessa [10]3 years ago

8 0

Hmmm thats a tricky question

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A major fishing company does its fishing in a local lake. The first year of the

Allisa [31]

The answer to your question is 7,600 fish

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3 years ago

The number of stamps that kaye and alberto had were in the ratio 5 : 3, respectively. after kaye gave alberto 10 of her stamps,

Gala2k [10]

K:A
5:3 (before)
15:9

since the total number of stamps didn't change, the total ratio should be the same.

7:5(after)
14:10

so this means 1 unit is 10stamps.

14-10=4
4 X 10= 40

Kaye have 40 more stamps than Alberto.

4 0

3 years ago

Find the area of the rhombus.<br> 7.5 yd<br> 13 yd<br> 13 yd<br> 7.5 yd<br> [ ? ] yd2

Doss [256]

Answer:

195

Step-by-step explanation:

4 0

2 years ago

A circular swimming pool is 21 feet in

Aleksandr [31]

Answer:

G. 66 feet

Step-by-step explanation:

Radius = 21/2 = 10.5

Circumference

2 × 3.14 × 10.5

65.94 feet

6 0

3 years ago

(6-3(cube root of 6)/(cube root of 9)

MatroZZZ [7]

For this case we must simplify the following expression:

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}$

Multiplying the numerator and denominator by $(\sqrt [3] {9}) ^ 2$

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =$

We rewrite:

$\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =$

By properties of powers we have that:

$a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =$

We rewrite, moving the exponent within the radical:

$\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {9 ^ 2}} {9} =\\\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {81}} {9} =$

We can rewrite $3 * 3 ^ 3 = 81$

$\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {3 * 3 ^ 3}} {9} =$

We simplify:

$\frac {(6-3 \sqrt [3] {6}) * 3 \sqrt [3] {3}} {9} =$

We apply distributive property:

$\frac {18 \sqrt [3] {3} -9 \sqrt [3] {18}} {9} =$

Simplifying we finally have:

$2 \sqrt [3] {3} - \sqrt [3] {18}$

Answer:

$2 \sqrt [3] {3} - \sqrt [3] {18}$

5 0

3 years ago