Answer:
∠ EFH = 112°
Step-by-step explanation:
∠ ACD and ∠ EFH are Alternate exterior angles and are congruent, thus
11x - 20 = 9x + 4 ( subtract 9x from both sides )
2x - 20 = 4 ( add 20 to both sides )
2x = 24 ( divide both sides by 2 )
x = 12
Thus
∠ EFH = 11x - 20 = 11(12) - 20 = 132 - 20 = 112°
hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = OP....p(-8,3)
r² = (OP)²
r² = (-8-0)² +(3-0)² = 64+9=73
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through P(-8, 3) is : x² +y² = 73</span></span>
Answer:
b<58/5
Step-by-step explanation:
The answer to the question is 1 and 3/4