<em><u>Complete Question:</u></em>
A colony of flowers is pollinated by hummingbirds and sunbirds. Let H represents the number of hummingbirds and S represent the number of sunbirds that must pollinate the colony so it can survive until next year.
6H+ 4S> 74
This year, 8 hummingbirds pollinated the colony. What is the least number of sun birds that must pollinate the colony to ensure that it will survive until next year?
<em><u>Answer:</u></em>
The least number of sun birds is 7
<em><u>Solution:</u></em>
Given inequality is:
6H + 4S > 74
Where,
H is the number of hummingbirds
S is the number of sunbirds
This year, 8 hummingbirds pollinated the colony
Substitute H = 8 in given inequality
6(8) + 4S > 74
48 + 4S > 74
Subtract 48 from both sides
48 + 4S - 48 > 74 - 48
4S > 26
Divide both sides by 4
S > 6.5
Hence the least number of sun birds is 7
It would be: 41/16.4 * 100 = 4100/16.4 = 250%
D for the same reason percents
Answer:
x(3y - 1) and (2a - 3)(2a + 3)
Step-by-step explanation:
(1)
3xy - x ← factor out x from each term
= x(3y - 1)
(2)
4a² - 9 ← is a difference of squares and factors in general as
a² - b² = (a - b)(a + b) , then
4a² - 9
= (2a)² - 3²
= (2a - 3)(2a + 3)
