Answer:
K = [H₂]² [ O₂] / [H₂O]²
Explanation:
The equilibrium constant of any reaction can be written as,
K = [product]/ [reactant]
For given reaction:
Chemical equation:
2H₂O → 2H₂ + O₂
equilibrium constant:
K = [H₂] [ O₂] / [H₂O]
In stoichiometric calculations, we will put the coefficient of balanced equation in given equilibrium constant equation.
K = [H₂]² [ O₂] / [H₂O]²
Answer:
1.135 M.
Explanation:
- For the reaction: <em>2HI → H₂ + I₂,</em>
The reaction is a second order reaction of HI,so the rate law of the reaction is: Rate = k[HI]².
- To solve this problem, we can use the integral law of second-order reactions:
<em>1/[A] = kt + 1/[A₀],</em>
where, k is the reate constant of the reaction (k = 1.57 x 10⁻⁵ M⁻¹s⁻¹),
t is the time of the reaction (t = 8 hours x 60 x 60 = 28800 s),
[A₀] is the initial concentration of HI ([A₀] = ?? M).
[A] is the remaining concentration of HI after hours ([A₀] = 0.75 M).
∵ 1/[A] = kt + 1/[A₀],
∴ 1/[A₀] = 1/[A] - kt
∴ 1/[A₀] = [1/(0.75 M)] - (1.57 x 10⁻⁵ M⁻¹s⁻¹)(28800 s) = 1.333 M⁻¹ - 0.4522 M⁻¹ = 0.8808 M⁻¹.
∴ [A₀] = 1/(0.0.8808 M⁻¹) = 1.135 M.
<em>So, the concentration of HI 8 hours earlier = 1.135 M.</em>
Answer:
Explanation:
Molarity is concentration measured in moles per liters. It is the number of moles of solute per liters of solution. The formula is:
We know the solution of HCl has a molarity of 0.5 molar and there are 0.8 liters of solution.
- 1 molar (M) is equal to 1 mole per liter.
- Let's convert the molarity of 0.5 M HCl to 0.5 mol HCl per liter. This will make unit cancellation easier.
The moles of solute or HCl are unknown, so we can use x. Now, we can substitute all known values into the formula.
Since we are solving for the moles of solute (x), we must isolate the variable. It is being divided by 0.8 liters. The inverse of division is multiplication, so we multiply both sides by 0.8 L.
The units of liters (L) cancel.
This solution contains <u>0.4 moles of HCl.</u>
Answer:
I believe the answer is conduction.
