2 years ago

What is the mass of 0.38 moles of cobalt (Co)?

Chemistry

1 answer:

marta [7]2 years ago

4 0

Answer:

The required mass is 22.04 g

Explanation:

We know,

Atomic mass of Co= 58g.

Now,

1 mole Co = 58 g

∴ 0.38 mole Co= (58 X 0.38) g

= 22.04 g

So, the required mass is 22.04 g

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2 years ago

The reaction of hydrogen and iodine to produce hydrogen iodide has a Kc of 54.3 at 703 K. Given the initial concentrations of H2

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Answer:

[HI] = 0.7126 M

Explanation:

Step 1: Data given

Kc = 54.3

Temperature = 703 K

Initial concentration of H2 and I2 = 0.453 M

Step 2: the balanced equation

H2 + I2 ⇆ 2HI

Step 3: The initial concentration

[H2] = 0.453 M

[I2] = 0.453 M

[HI] = 0 M

Step 4: The concentration at equilibrium

[H2] = 0.453 - X

[I2] = 0.453 - X

[HI] = 2X

Step 5: Calculate Kc

Kc = [Hi]² / [H2][I2]

54.3 = 4x² / (0.453 - X(0.453-X)

X = 0.3563

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[I2] = 0.453 - 0.3563 = 0.0967 M

[HI] = 2X = 2*0.3563 = 0.7126 M

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