A jogging trail measures 252 feet from start to finish. Cheryl ran the trail 2 times.

Pre image ABCD was dilated to be image A’B’C’D, where the center of dilation is the origin. What scale factor was used in the di

ArbitrLikvidat [17]

Answer:

The scale factor is 0.25

Step-by-step explanation:

we know that

The dilation is a non-rigid transformation that produce similar figures

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

In this problem

ABCD and A'B'C'D' are similar

therefore

$\frac{A'B'}{AB}=\frac{B'C'}{BC}=\frac{C'D'}{CD}=\frac{A'D'}{AD}$

Find the scale factor

Looking at the graph

we have

$A'B'=1\ unit\\AB=4\ units$

Let

z ---> the scale factor

$z=\frac{A'B'}{AB}$

substitute the values

$z=\frac{1'}{4}=0.25$

8 0

3 years ago

Can someone please help me? :(

den301095 [7]

Answer:

a=(0,0)

Step-by-step explanation:

i actually dont know but thnks for the points BTW

4 0

3 years ago

A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent

kotykmax [81]

Answer:

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

Step-by-step explanation:

$\bar X_{1}=15$ represent the mean for sample 1

$\bar X_{2}=18$ represent the mean for sample 2

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=49$ sample size for the group 2

$n_{2}=64$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=49+64-2=111$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897$

P value

Since is a bilateral test the p value would be:

$p_v =2*P(t_{111}$

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

7 0

3 years ago

Joan flipped a coin 100 times during a mathematics experiment. The coin landed on tails 36 times. Based on Joan's results, which

Darina [25.2K]

It is A because it can’t be B and it can’t be C and it can’t be D so my answer is A

3 0

3 years ago

Helpppp? PLease im very confused

kompoz [17]

Answer:

Yes

Step-by-step explanation:

There is a linear relationship, so there is a constant change in the graph and thus a proportional relationship.

3 0

4 years ago