The corresponding logical address is 200.
If a program is operating with execution-time binding, the physical address generated will be 300. However, if the relocation register is set to 100, the corresponding logical address will be 200.
This is because the relocation register is used to offset the physical address, so that it can be used to calculate the logical address.
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Answer:
Option B is the correct option.
Explanation:
The following answer is true because when the person completed our training of a decision tree and after the following presentation he getting not good working performance on both side i.e., test sets and during the training period. After the training there is no bug on the implementation of the presentation then, he has to increase the rate of the learning.
Answer:
boolean isEven = false;
if (x.length % 2 == 0)
isEven = true;
Comparable currentMax;
int currentMaxIndex;
for (int i = x.length - 1; i >= 1; i--)
{
currentMax = x[i];
currentMaxIndex = i;
for (int j = i - 1; j >= 0; j--)
{
if (((Comparable)currentMax).compareTo(x[j]) < 0)
{
currentMax = x[j];
currentMaxIndex = j;
}
}
x[currentMaxIndex] = x[i];
x[i] = currentMax;
}
Comparable a = null;
Comparable b = null;
if (isEven == true)
{
a = x[x.length/2];
b = x[(x.length/2) - 1];
if ((a).compareTo(b) > 0)
m = a;
else
m = b;
}
else
m = x[x.length/2];
Answer:
I don't think so. In today's computer era, many different solution directions exist for any given problem. Where OOP used to be the doctrine of choice, now you would consider it only when the problem at hand fits an object-oriented solution.
Reason 1: When your problem can be decomposed in many different classes with each many instances, that expose complex interactions, then an OO modeling is justified. These problems typically produce messy results in other paradigms.
Reason 2: The use of OO design patterns provides a standardized approach to problems, making a solution understandable not only for the creator, but also for the maintainer of code. There are many OO design patterns.
