Answer:
Question 1: 
Question 2:
A. 
B. 
C. 
Step-by-step explanation:
Conditional probability is defined by

with P(A and B) beeing the probability of both events occurring simultaneously.
Question 1:
B: Baseball League Championships won, beeing

Y: Championships won by the 10 - 12 years old, beeing

then
P( B and Y)= \frac{ 2 }{ 16 }[/tex]
By definition,

Question 2.A:
Y: Championships won by the 10 - 12 years old, beeing

B: Baseball League Championships won, beeing

then
P( B and Y)= \frac{ 2 }{ 16 }[/tex]
By definition,

Question 2.B:
Z: Championships won by the 13 - 15 years old, beeing

B: Baseball League Championships won, beeing

then
P( Z and B)= \frac{ 1 }{ 16 }[/tex]
By definition,

Question 3.B
Y: Championships won by the 10 - 12 years old, beeing

Z: Championships won by the 13 - 15 years old, beeing

then

B: Baseball League Championships won, beeing

so

By definition,
