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3 years ago

What is the distance between the points (-30,10and(30,19) in the xy-plane

Mathematics

1 answer:

Alex787 [66]3 years ago

5 0

Answer:

√3681

Step-by-step explanation:

D= √(30+30)^2+(19-10)^2

D= √60^2+9^2

D= √3600+81

D= 3681

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I do not know this answer

PilotLPTM [1.2K]

Answer:

(-6,3)

Step-by-step explanation:

H is 1 point above y=4, so H' will be 1 point <em>below </em>y=4.

Hope this helps!

ibrahim

4 0

2 years ago

How would you solve for x here

Alex Ar [27]

Answer:

x=-1.30068.......

Step-by-step explanation:

x( 3x^2 - 2) = -4

Distribute

3x^3 - 2x = -4

Add 4 to each side

3x^3 - 2x +4 = 0

Plot using a graphing calculator

x=-1.30068.......

5 0

3 years ago

Four less than the product of one and a number x.

BaLLatris [955]

X-4 These characters are for >20 rule

3 0

3 years ago

3(2x+6) = 2(4x-5)<br><br> plshelp

umka21 [38]

Answer:

x = 14

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

Step 2: Subtract 8x from both sides.

Step 3: Subtract 18 from both sides.

Step 4: Divide both sides by -2.

7 0

3 years ago

Read 2 more answers

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°

Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = $c^{2}$ = $a^{2} + b^{2}$

a = 7 and b = 11

$a^{2}$ = 49

$b^{2}$ = 121

Plugging in the values, we will get:

$c^{2}$ = 49 + 121

$c^{2}$ = 170

c = $\sqrt{170}$

To calculate the unknown angle B, we can use law of sine.

Law of sine = $\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$

So,

$\frac{c}{sinC}$ = $\frac{b}{sinB}$

$\frac{\sqrt{170} }{sin90}$ = $\frac{11}{sinB}$

Sin90 = 1

sinB = $\frac{11}{\sqrt{170} }$

B = $sin^{-1}$ ( $\frac{11}{\sqrt{170} }$ )

B = 57.5°

8 0

3 years ago