Ask question

Ask question

All categories

3 years ago

15

Evaluate the expression when y=-3

a1" title="y {}^{2} + 5y - 4" alt="y {}^{2} + 5y - 4" align="absmiddle" class="latex-formula">

1 answer:

Zielflug [23.3K]3 years ago

3 0

(-3)^2+5(-3)-4

9-15-4

=-10

You might be interested in

What is this please help

sweet-ann [11.9K]

Answer:

Absolute value means how far are you from zero on the number line.

absolute value of | -18| for example is 18

this means that you are at -18 on the number line that is 18 points away from zero.

and absolute value of |18 | is 18

this means that you are at point 18 on the positive direction on the number line. That is 18 points away from zero.

Step-by-step explanation:

4 0

3 years ago

What is the slope of the line though the points ( -6, 3) and ( -7,-4)

DiKsa [7]

I believe the answer is 7

8 0

3 years ago

larry claims that 14+12×8+12 and14×12+8×12 are equivalent because they have the same digits and the same operations

JulsSmile [24]

They are not the same because one they dont get the same answer and one of the signs are different so it has changed the answer

7 0

3 years ago

Read 2 more answers

Whadt is the first and second quotient of 1178 divided by 31

Law Incorporation [45]

Answer:

its 38

Step-by-step explanation:

use a calculator like i did :)

8 0

2 years ago

12. Let yo = O. Write parametric equations to represent the path of the ballsthrown by Sami and T'Aisha given the following cond

ira [324]

SOLUTION:

We want to write the x and y parametric equation for Sami and T'Aisha given their following data.

$\begin{gathered} Sami:v_0=15\frac{ft}{s},\theta=35^o,y_0=5.4ft \\ T^{\prime}Aisha:v_0=19\frac{ft}{s},\theta=50^o,y_o=5.8ft \\ x_0=0 \end{gathered}$

The parametric equations for x and y are given by;

$\begin{gathered} x(t)=x_0+(v_0cos\theta)t \\ y(t)=y_0+(v_0sin\theta)t+0.5gt^2 \end{gathered}$

Inserting, the values, we have; For Sami;

$\begin{gathered} Sami: \\ x\left(t\right)=15cos35t, \\ y\left(t\right)=5.4+15sin35t-16t^2 \end{gathered}$

For T'Aisha;

$\begin{gathered} T^{\prime}Aisha: \\ x\left(t\right)=19cos50t, \\ y\left(t\right)=5.8+19sin50t-16t^2 \end{gathered}$

4 0

1 year ago