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Hatshy [7]
3 years ago
15

Evaluate the expression when y=-3

a1" title="y {}^{2} + 5y - 4" alt="y {}^{2} + 5y - 4" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Zielflug [23.3K]3 years ago
3 0

(-3)^2+5(-3)-4

9-15-4

=-10

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6 ten thousands 4 hundreds × 10
Katyanochek1 [597]

Answer:

604,000

Step-by-step explanation:

60,400 x 10

add one zero onto the end and replace the comma.

604,000

8 0
3 years ago
At a wedding reception, the caterer served fishing chicken. The fish dinner cost $12 per person in the chicken cost $9 per perso
maw [93]

Answer:

80 persons haf fish and 152 persons had chicken

Step-by-step explanation:

Given data

let the number of persons that had fish be x and chicken be y

so

12x+9y=2544------------------1

x+y= 232------------------------2

from 2

x= 232-y

substitute the value of x in 1

12(232-y)+9y=2544

2784-12y+9y=2544

2784-3y=2544

3y= 2784-2544

3y=240

y= 240/3

y=80

put y= 80 in 2

x+80= 232

x= 232-80

x=152

Hence 80 persons haf fish and 152 persons had chicken

5 0
2 years ago
I need help. i don’t understand this question .
user100 [1]

So the question is asking to solve for y

You know RS=7y-4

You know ST=y+5

You know RT=28

RS+ST=RT as shown in the diagram, This means that you can use that equation and replace RS,ST, and RT with what you know they are equal too. So you end up with the equation:

(7y-4)+(y+5)=28, Now you have to solve for y

7y-4+y+5=28

8y+1=28

8y=27

y=3.375

6 0
3 years ago
How is this written in an expanded version?
Yuri [45]

Powers distribute over multiplications:

(ab)^c = a^c\cdot b^c

So, you have

(3k^5)^2 = 3^2 \cdot (k^5)^2

Now, 3^2 is simply 9.

As for (k^5)^2, we have to use the rule

(a^b)^c = a^{bc}

to get

(k^5)^2=k^{5\cdot 2}=k^{10}

So, the final answer is

(3k^5)^2 =9k^{10}

5 0
3 years ago
Read 2 more answers
Solve problem soon, will give brainliest
suter [353]

Answer:

it is f from the going vertical

8 0
2 years ago
Read 2 more answers
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