Using the rule of thirds to evaluate the composition of a well-crafted painting, the eye should be attracted to A. one or more p
2 answers:
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Answer:
Part 1 , not significant
Part II, significant
Step-by-step explanation:
Given that a heterozygous white-fruited squash plant is crossed with a yellow-fruited plant, yielding 200 seeds. of these seeds, 110 produce white-fruited plants while only 90 produce yellow-fruited plants
(Two tailed chi square test)
We assume H0 to be true and find out expected
If H0 is true expected would be 100 white and 100 yellow
Chi square =
df = 1
p value = 0.152799
Since p value > 0.05 at 5% level we accept that the colours are equally likely
2)
Here observed are 1100 and 900
Expected 1000 & 1000
df = 1
Chi square =
p value <0.0001
These results are here statistically significant.
Answer:
If we compare the p value obtained with the significance level given we have
so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 2% of significance the proportion of residents who favored annexation is not significantly higher than 0.39.
Step-by-step explanation:
1) Data given and notation
n=1000 represent the random sample taken
estimated proportion of residents who favored annexation
is the value that we want to test
represent the significance level
Confidence=98% or 0.98
z would represent the statistic (variable of interest)
represent the p value (variable of interest)
2) Concepts and formulas to use
We need to conduct a hypothesis in order to test the claim that the proportion is higher than 0.39:
Null hypothesis:
Alternative hypothesis:
When we conduct a proportion test we need to use the z statistic, and the is given by:
(1)
The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value
.
3) Calculate the statistic
Since we have all the info requires we can replace in formula (1) like this:
4) Statistical decision
It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.
The significance level provided . The next step would be calculate the p value for this test.
Since is a right tailed test the p value would be:
If we compare the p value obtained with the significance level given we have
so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 2% of significance the proportion of residents who favored annexation is not significantly higher than 0.39.