This is a pythagorean theorem problem
When solving for the sides of a right triangle... a^2 + b^2 = c^2
Therefore, 7^2 + b^2 = 25^2
b^2 = 25^2 - 7^2 = 576
b = sqrt(576) = 24
Answer: A 24
FVAD=8000[((1+0.10/4)^(4*4)-1)/(0.10/4)]*(1+0.10/4)
FVAD=158917.84
Answer:
The second option is the correct answer
The sequence is : 0, -1, -6, -31, -156
Step-by-step explanation:
It is given that,
The recursive formula , an = 5a(n-1) - 1 and a1 = 0
<u>To find a2, a3, a4, a5
</u>
a2 = 5a1 -1 = 5x0 - 1 = -1
a3 = 5a2 - 1 = (5x -1 ) - 1 = - 5 - 1 = -6
a4 = 5a3 - 1 =(5x -6) - 1 = -30 - 1= -31
a5 = 5a4 - 1 = (5 x -31 ) - 1 = -155 -1 = -156
Therefore the resulting sequence is
0, -1, -6, -31 ,-156
Answer:
5x(2 - 3x³)
Step-by-step explanation:
10x-15x^4
The GCF( Greatest Common Factor) of 10x-15x^4 is 5x
Solve:
10x/5x = 2
-15^4/5x = -3x³
Final answer is
5x(2 - 3x³)
<u>Check</u>
5x(2 - 3x³)
distribute
5x(2) + 5x(-3x³)
10x - 15x^4
The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
To learn more on quadratic functions: brainly.com/question/5975436
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