Question

The upper-left coordinates on a rectangle are (-4,4), and the upper-right coordinates are (4,4).The rectangle has an area of 8 square units. Draw the rectangle on the coordinate plane below.

Answer 1

Answer:

Then the coordinate of point $C$ is $(4,3)$, and the coordinate of point $D$ is $(-4,3)$.

Step-by-step explanation:

Given that,

                The upper-left coordinate on a rectangle is $(-4,4)$.

                The upper-right coordinate on a rectangle is $(4,4)$.

                Area of rectangle is $8$ square unit.

Let, $ABCD$ is a rectangle.

The coordinate of point $A$ is $(-4,4)$ and the coordinate of point $B$ is $(4,4)$.

Diagram of rectangle $ABCD$ is shown below:

Now,

$AB=$ $\sqrt{(4+4)^{2}+(4-4)^{2} }$

      $=\sqrt{(64+0)}$

      $=\sqrt{64}$

      $= 8\ unit$

∵Area of rectangle = Length $\times$ Breadth

$8$ square unit = $8\ unit$ $\times Breadth$

∴ Breadth $=1\ unit$

$BC=\sqrt{(4-4)^{2}+(y-4)^{2} }$

      $=\sqrt{(y-4)^{2} }$

⇒ $1$$=\sqrt{(y-4)^{2} }$

squaring both sides, we get

⇒ $1=(y-4)^{2}$

⇒ $(y-4)$ = ±$1$

∴$y=3$

Then the coordinate of point $C$ is $(4,3)$, and the coordinate of point $D$ is $(-4,3)$.

Answer 2

Answer: A) upper-left (-4,4), B) upper-right (4,4),

C) Lower-Right (4,3), D) lower-left (-4,3)