Answer:
Q1: p = - 33
Q2: d = - 99
Q3: t = - 13
Step-by-step explanation:
Q1: 
We solve this taking LCM.
We get: 
Q4: 
Again we proceed like Q1 by taking LCM.
We get: 
Q7: 5t + 12 = 4t - 1
We club the like terms on either side.
Hence, the answer.
Answer:
404 cm³ Anyway... Look down here for my explanation.
Step-by-step explanation:
Let's Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth on your paper. A right-angled triangle is formed too. The Length of side to the water-surface is 5 cm, the hospot is 7 cm.
We Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7)
44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8°
The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram.
Shaded area 88.8/360*area of circle - ½*7*788.8°
= 88.8/360*π*7² - 24.5*sin 88.8°
13.5 cm²
(using area of ∆ = ½.a.b.sin C for the triangle)
Volume of water = cross-sectional area * length
13.5 * 30 cm³
404 cm³
3/4-3=43 Thsts the answer hopes it help
Answer:
<h2>C. 16,802</h2>
Step-by-step explanation:
h h h h h h h h h h
Since they are intersecting lines, you would equal them to each other.
(5x+4)= (8x-71)
-8x. -8x
-3x + 4 = -71
- 4. -4
-3x = -75
Divide 3x by both sides gets you x = 25
